我有一个这样定义的数据集:
var hour = data.crossfilter.dimension(function(d){ return d.date.getHours() + d.date.getMinutes() / 60; });
var hours = hour.group(Math.floor);
生成的结果 ( hours.all()
) 如下所示:
[0, 124]
[1, 25]
[2, 5]
[3, 2]
[5, 339]
[6, 11648]
[7, 16334]
[8, 15919]
[9, 14078]
[10, 13816]
[11, 14646]
[12, 15079]
[13, 13718]
[14, 13947]
[15, 14055]
[16, 13995]
[17, 16166]
[18, 14958]
[19, 13991]
[20, 12769]
[21, 10638]
[22, 3939]
[23, 892]
3
请注意,5
(4
缺失)之间存在数据差距。如何配置交叉过滤器来填补空白0
?