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由于我有一个使用大量 http 请求的脚本,因此我决定创建一个函数来执行此操作(而不是一遍又一遍地使用相同的代码块......)。但我面临的问题是如何将 html 输出从 file_a.py 返回到 file_b.py?因为我需要输出来解析一些结果?

文件_a.py

def invokeServer(proxyUser,proxyPass,proxyHost,iserver,isService,login,password):

  proxy_auth = "http://"+proxyUser+":"+proxyPass+"@"+proxyHost
  proxy_handler = urllib2.ProxyHandler({"http": proxy_auth})
  opener = urllib2.build_opener(proxy_handler)
  opener = urllib2.build_opener()
  urllib2.install_opener(opener)
  request = urllib2.Request("http://"+iserver+""+isService)
  base64string = base64.encodestring('%s:%s' % (login, password)).replace('\n', '')
  request.add_header("Authorization", "Basic %s" % base64string)
  response = urllib2.urlopen(request)
  html= response.read()
  return html

文件_b.py

from file_a import invokeServer
invokeServer(proxyUser,proxyPass,proxyHost,iserver,isService,login,password)

# From this line bellow, i need to use the html result from file_a.py
doc = LH.fromstring(html) 
LE.strip_tags(doc,'b')
data_list = doc.xpath("//td[text()='triggerNameList']/following-sibling::*")[0]
triggerName = data_list.xpath("//td[text()='triggerName']/following-sibling::*/text()")

提前致谢。

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1 回答 1

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将其存储在变量中:

html = invokeServer(... 
于 2012-09-04T11:34:32.310 回答