请参阅我关于AsyncTask 中 IllegalStateException 的问题。
我从此任务的 onPostExecute() 调用了以下 AsyncTask(在此链接中引用)。
public class SaveImageAsync extends AsyncTask<Context, Integer, String> {
private Bitmap bitmap = null;
private ArrayList<String> imageUrls = null;
private ArrayList<ImageView> imageViews = null;
int index = 0;
public SaveImageAsync(ArrayList<ImageView> imageViews,
ArrayList<String> imageUrls) {
this.imageUrls = imageUrls;
this.imageViews = imageViews;
}
@Override
protected String doInBackground(Context... params) {
boolean bRC;
String imageName, imageLocalPath, imageURL;
try {
for (int i = 0; i < imageUrls.size(); i++) {
imageURL = imageUrls.get(i);
String[] strSplittedImagePath = imageURL
.split("/");
if ((strSplittedImagePath != null)
&& (strSplittedImagePath.length >= 1)) {
imageName = strSplittedImagePath[(strSplittedImagePath.length - 1)];
} else {
imageName = imageURL;
}
imageLocalPath = path + imageName;
bRC = doesFileExists(imageLocalPath);
if (bRC == false) {
getImageFromServer(CommonSettings.mSTstrBaseURL
+ imageURL, imageLocalPath);
}
try {
bitmap = BitmapFactory
.decodeFile(imageLocalPath);
} catch (Exception e) {
}
if (bitmap == null) {
try {
new File(imageLocalPath).delete();
} catch (Exception e1) {
}
getImageFromServer(CommonSettings.mSTstrBaseURL
+ imageURL, imageLocalPath);
bitmap = BitmapFactory
.decodeFile(imageLocalPath);
}
Thread.sleep(300);
publishProgress();
}
} catch (InterruptedException e) {
e.printStackTrace();
Log.w(LOG_TAG,
"Got InterruptedException inside AsyncTask SaveImageAsync : "
+ e);
}
return null;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
}
@Override
protected void onProgressUpdate(Integer... values) {
super.onProgressUpdate(values);
ImageView imageView = imageViews.get(index);
while (imageView == null) {
index = index + 1;
imageView = imageViews.get(index);
}
imageView.setScaleType(ScaleType.FIT_XY);
imageView.setImageBitmap(bitmap);
index = index + 1;
//bitmap.recycle();
}
public boolean getImageFromServer(String url, String localPath) {
boolean bReturn = false;
File objNewFile;
try {
objNewFile = new File(localPath);
if (!objNewFile.exists()) {
objNewFile.createNewFile();
}
BufferedInputStream objBufferedInput = new BufferedInputStream(
new java.net.URL(url).openStream());
FileOutputStream objFileOutput = new FileOutputStream(objNewFile);
BufferedOutputStream objBufferOutput = new BufferedOutputStream(
objFileOutput, 1024);
byte[] data = new byte[1024];
int x = 0;
while ((x = objBufferedInput.read(data, 0, 1024)) >= 0) {
objBufferOutput.write(data, 0, x);
}
objFileOutput.flush();
objBufferOutput.flush();
objFileOutput.close();
objBufferOutput.close();
objBufferedInput.close();
bReturn = true;
} catch (IOException e) {
} catch (Exception ex) {
}
return bReturn;
}
}
当按下返回按钮并加载此任务时,它会在 decodeFile() 处引发 OutOfMemoryException。为什么会发生这种情况以及如何解决这个问题?
谢谢