假设有一个数组
(1) x=np.array([[1,2],[1,2],[1,2]])
和第二个数组
(2) y=np.array([[1],[1,2],[1,2,3]])
该命令size(x)返回沿每个轴的所有元素的总数。在这种情况下6。但是，size(y)返回3. 这一定是因为 numpy 在这种情况下将 (2) 解释为沿一个轴的三个元素（三个子数组），尽管shape(y)返回(3, ). 我现在的问题是：如何让 numpy 将 (2) 解释为具有三个轴的数组，以便size(y)返回所有原子元素的总数，即6？
I don't think it's possible to get the number of elements from y without looping over the objects.
The problem is that the elements of y are not numbers, they are objects (lists). Numpy does not support lists of lists and therefore it stores it as a 1-dimensional array of objects. I don't think there are Numpy methods to get the total number of elements in y.