我似乎无法弄清楚如何正确显示从数据库输出 mysql 数据的选择菜单。我想输出博客标题,以便用户可以根据他们在选择菜单中选择的类别将图片上传到所选博客。以下是文件:
形式:
<form action="" method="post" enctype="multipart/form-data">
<p>Choose a file:<br /><input type="file" name="image" /></p>
<p>
Choose an album:<br />
<select name="album_id">
<?php
foreach ($albums as $album){
echo '<option value="', $album['id'], '">', $album['name'], '</option>';
}
?>
</select><br /><br />
Choose an blog:<br />
<select name="post_id">
<?php
foreach ($posts as $post){
echo '<option value="', $post['id'], '">', $post['title'], '</option>';
}
?>
</select>
</p>
<p><input type="submit" value="Upload" /></p>
</form>
这是posts.php文件:
<?php
//checks if the given post id is in the table
function valid_pid($pid) {
$pid = (int)$pid;
$total = mysql_query("SELECT COUNT(`post_id`) FROM `posts` WHERE `post_id` = {$pid}");
$total = mysql_result($total, 0);
if ($total != 1) {
return false;
}else{
return true;
}
}
//gets a summary of all blog posts
function get_posts() {
$sql = "SELECT
`posts`.`post_id` AS `id`,
`posts`.`post_title` AS `title`,
LEFT(`posts`.`post_body`, 512) AS `preview`,
`posts`.`post_user` AS `user`,
DATE_FORMAT(`posts`.`post_date`, '%m-%d-%Y %H:%i:%s') AS `date`,
`comments`.`total_comments`,
DATE_FORMAT(`comments`.`last_comment`, '%m-%d-%Y %H:%i:%s') AS `last_comment`
FROM `posts`
LEFT JOIN(
SELECT
`post_id`,
COUNT(`comment_id`) AS `total_comments`,
MAX(`comment_date`) AS `last_comment`
FROM `comments`
GROUP BY `post_id`
) AS `comments`
ON `posts`.`post_id` = `comments`.`post_id`
ORDER BY `posts`.`post_date` DESC";
$posts = mysql_query($sql);
$rows = array();
while (($row = mysql_fetch_assoc($posts)) !== false) {
$rows[] = array(
'id' => $row['id'],
'title' => $row['title'],
'preview' => $row['preview'],
'user' => $row['user'],
'date' => $row['date'],
'total_comments' => ($row['total_comments'] === null) ? 0 : $row['total_comments'],
'last_comment' => ($row['last_comment'] === null) ? 'none' : $row['last_comment']
);
}
return $rows;
}
//gets a single post from the table
function get_post($pid) {
$pid = (int)$pid;
$sql = "SELECT
`post_title` AS `title`,
`post_body` AS `body`,
`post_user` AS `user`,
`post_date` AS `date`
FROM `posts`
WHERE `post_id` = {$pid}";
$post = mysql_query($sql);
$post = mysql_fetch_assoc($post);
$post['comments'] = get_comments($pid);
return $post;
}
//adds a new blog entry
function add_post($name, $title, $body) {
$name = mysql_real_escape_string(htmlentities($name));
$title = mysql_real_escape_string(htmlentities($title));
$body = mysql_real_escape_string(nl2br(htmlentities($body)));
mysql_query("INSERT INTO `posts` (`post_user`, `post_title`, `post_body`, `post_date`) VALUES ('{$name}', '{$title}', '{$body}', NOW())");
}
?>
谢谢你的帮助!
-TechGuy24