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我不确定它是否是一个明确的问题。我想要的是从 web 服务中检索 xml 响应。我有 web 服务的 url、用户名、密码、xml 正文等详细信息。我可以在字符串中获取 xml 响应变量。有人可以为我提供一个有用的链接来解析 xml 字符串吗？我共享用于检索 xml 的代码注意：-确保您有 commons-httpclient-3.1、commons-codec-1.6、commons-logging-1.1.1、junit-4.10 库

 import java.io.BufferedReader;
    import java.io.InputStream;
    import java.io.InputStreamReader;

    import org.apache.commons.httpclient.HttpClient;
    import org.apache.commons.httpclient.HttpStatus;
    import org.apache.commons.httpclient.UsernamePasswordCredentials;
    import org.apache.commons.httpclient.auth.AuthScope;
    import org.apache.commons.httpclient.methods.PostMethod;


    public class AbstractService
    {
        @SuppressWarnings( "deprecation" )
        protected String postForString( final String requestUrl, final String requestBody )
        {
            final StringBuilder result = new StringBuilder();
            HttpClient client = new HttpClient();

            try
            {
                PostMethod postRequest = new PostMethod( getAbsoluteUrl( requestUrl ) );

                postRequest.addRequestHeader( WebServiceClientConstants.CONTENT_TYPE,
                        WebServiceClientConstants.APPLICATION_XML );
                postRequest.setRequestBody( WebServiceClientConstants.REQUEST_HEADER + requestBody );

                client.getState()
                        .setCredentials(
                                new AuthScope( WebServiceClientConstants.HOST, WebServiceClientConstants.PORT,
                                        AuthScope.ANY_REALM ),
                                new UsernamePasswordCredentials( WebServiceClientConstants.USERNAME,
                                        WebServiceClientConstants.PASSWORD ) );

                int responseCode = client.executeMethod( postRequest );

                System.out.println( "[REQUEST][" + postRequest.getURI().toString() + "]" );
                System.out.println( "[STATUS][" + postRequest.getStatusLine().toString() + "]" );

                if ( HttpStatus.SC_OK == responseCode )
                {
                    String data = null;
                    final InputStream responseStream = postRequest.getResponseBodyAsStream();
                    final BufferedReader bufferedReader = new BufferedReader( new InputStreamReader( responseStream,
                            WebServiceClientConstants.UTF_8_ENCODING ) );

                    while ( ( data = bufferedReader.readLine() ) != null )
                    {
                        result.append( data );
                    }
                }

                postRequest.releaseConnection();

            }
            catch ( Exception e )
            {
                e.printStackTrace();
            }

            return result.toString();
        }

        private String getAbsoluteUrl( String requestUrl )
        {
            return WebServiceClientConstants.SERVIE_BASE_URL + requestUrl;
        }
    }

WebServiceClientConstants 接口

package com.test.service.info;
public interface WebServiceClientConstants
{
    String  PROTOCOL        = "http://";
    String  HOST            = "youraddress.blah.test.com";
    Integer PORT            = 8080;
    String  SERVIE_BASE_URL = "http://youraddress.blah.test.com:8080/test/seam/resource/Services/";
    String  USERNAME        = "Username";
    String  PASSWORD        = "password";
    String  REQUEST_HEADER  = "<?xml version=\"1.0\"?>";
    String  CONTENT_TYPE    = "Content-Type";
    String  APPLICATION_XML = "application/xml";
    String  UTF_8_ENCODING  = "UTF-8";
}

菜单服务接口

public interface MenuService
{
    String getMenu();
}

MenuServiceImpl.java

public class MenuServiceImpl extends AbstractService implements MenuService
{
    @Override
    public String getMenu()
    {
        String requestUrl = "getMenu";
        String requestBody = "<ServiceRequest>" + "<ShortName>AppName</ShortName>"
                + "</ServiceRequest>";

        return postForString( requestUrl, requestBody );
    }
}

然后在一些活动中写

 MenuService menuService = new MenuServiceImpl();
        String prMenu = menuService.getMenu();
        Assert.assertNotNull( prMenu );

        test.setText(prMenu);

现在我将 xml 响应存储在 prMenu 变量中。它看起来像这样 http://www.coders-global.com/works/dev/menuserivicetemp.xml。现在我该如何解析这个 Xml 字符串。请采取看了一下链接。它看起来很复杂，我之前在其他一些线程中询问过如何解析这个链接，并且回复没有那么有用。如果有任何有用的链接或建议，请告诉。

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1 回答 1

0

您的问题似乎相当于“我如何解析存储在内存中的 XML 内容”，因为您似乎能够从远程服务器正确获取数据。

本质上，Java 库中内置了两种工具，分别称为 SAX 和 DOM 解析器。这两个选项的工作方式完全不同，重要的是您要了解差异并在它们之间进行明智的选择。

Here is an example of using the DOM parser in android XML Parsing Tutorial which is probably the direction you want to take given the low volume of the data.

PS: also using String.append as you do is pretty bad from a performance point of view - you need to look at the stringbuilder classes that are optimised for this kind of task.

于 2012-09-03T12:16:22.903 回答