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我还是新手，但我认为我很接近。我的任务是计算平均值、中位数和众数，然后：

  • 提示用户输入数字列表（提示：确保有一种方式让用户表明他们已完成提供数字列表）
  • 打开一个包含数字列表的文件
  • 计算数字列表的平均值、统计中位数和众数
  • 将您的答案存储在另一个文件中
  • 询问用户是否想查看答案，如果答案是肯定的，则打开文件并显示数字

我想让文件更“可读”。我现在得到的结果的一个例子是：

(lp1
S'3,5,6'
p2
aF4.666666666666667
aF5
aF3
a.

任何帮助将不胜感激！

这是我的代码：

def mean(numbers):
    average = 0
    for number in numbers:
        average += number
    return average / float(len(numbers))

def median(numbers):
    middle = []
    for number in numbers:
        middle.append(number)
    middle.sort()
    middleValue = len(middle) / 2
    if len(middle) % 2 == 1:
        return middle[middleValue]
    else:
        return (middle[middleValue] + middle[middleValue - 1]) / 2

def mode(numbers):
    frequency = {}
    for number in numbers:
        times = frequency.get(number, None)
        if times == None:
            frequency[number] = 1
        else:
            frequency[number] = times + 1

    maxValue = max(frequency.values())
    for modeFreq in frequency:
        if frequency[modeFreq] == maxValue:
            return modeFreq        

import cPickle as pickle

def main():
    user_in = raw_input("Enter a list of numbers seperated by commas: ")
    numbers_as_strings = user_in.replace(' ', '').split(',')
    numbers = [float(x) for x in numbers_as_strings]
    if not user_in:
        return 0
    else:
        print "\nYour inputs: ", user_in, '\n'
        print "   Mean = ", mean(numbers)
        print " Median = ", median(numbers)
        print "   Mode = ", mode(numbers), '\n'
        pckl_file = file("mean_medi_mode.txt", "w")
        pickle.dump([user_in, mean(numbers),median(numbers),mode(numbers)],pckl_file)
main()

while True:
    answer = raw_input('Would you like to open a file with your results? ')
    if answer.strip() in "y Y yes Yes YES".split():
        f = open("mean_medi_mode.txt", 'r')
        for line in f:
            print line,
        print 'Done'
        break
    elif answer.strip() in "n N no No NO".split():
        print 'Done'
        break
4

2 回答 2

1

当重新打开一个 pickle 文件（这不是一种人类可读的文本格式）时，使用pickle.load：

given, average, median, mode = pickle.load(f)

而不是你的for line in f: print line陈述。您的输出是 pickle 转储的原始内容，其中包含您保存的结果：

>>> import cPickle
>>> p = '''\
... (lp1
... S'3,5,6'
... p2
... aF4.666666666666667
... aF5
... aF3
... a.
... '''
>>> cPickle.loads(p)
['3,5,6', 4.666666666666667, 5.0, 3.0]

对于您的目的，泡菜格式可能有点笨拙。使用更轻松的、人类可读的格式，例如json或csv可能更适合您的需求。

于 2012-09-03T12:09:01.667 回答
1

尝试使用该json模块。它易于使用且易于阅读

import json
code...
def main():
    user_in = raw_input("Enter a list of numbers seperated by commas: ")
    numbers_as_strings = user_in.replace(' ', '').split(',')
    numbers = [float(x) for x in numbers_as_strings]
    if not user_in:
        return 0
    else:
        print "\nYour inputs: ", user_in, '\n'
        print "   Mean = ", mean(numbers)
        print " Median = ", median(numbers)
        print "   Mode = ", mode(numbers), '\n'
        json.dump([user_in, mean(numbers), median(numbers), mode(numbers)], fp)

然后：

def print(fp):
    user_in, mean, median, mode = json.load(fp)
    print "\nYour inputs: ", user_in, '\n'
    print "   Mean = ", mean
    print " Median = ", median
    print "   Mode = ", mode, '\n'
于 2012-09-03T12:11:21.767 回答