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在这样的一行中:
something "one!", "and two", "and three", "and more"
我应该如何使用命令 ci" 来替换 "and three"?
我尝试了一些没有运气的组合组合。
首先导航到所需的子字符串:
/three
或在行中:
f";;;;
(移动到接下来的"5 次)
"
或者
f,;
然后,ci"zaps 将光标留在空引号内插入的字符串
ci"
移入子字符串:
2发
然后替换和三个:
词"