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我有 2 个文本框,我在其中提供源地址和目标地址。

1) 来源 = SHAHIBAUG UNDER BRIDGE, Shahibagh, Ahmedab​​ad, Gujarat

2) 目的地 = CG Road, Shreyas Colony, Navrangpura, Ahmedab​​ad, Gujarat

距离 = 4.6(来自谷歌地图) && 2.6656852(使用距离定位方法)

final ProgressDialog dialog = ProgressDialog.show(AutoActivity.this, "Fare", "test");

            new Thread(new Runnable() {
                @Override
                public void run() {
                    try {
                        Location source_location = new Location("");
                        Location destination_location = new Location("");
                        Geocoder geoCode = new Geocoder(getApplicationContext());

                        source_location.setLatitude(geoCode.getFromLocationName(source_input.getText().toString(), 1).get(0).getLatitude());
                        source_location.setLatitude(geoCode.getFromLocationName(source_input.getText().toString(), 1).get(0).getLongitude());
                        source_location.set(source_location);

                        destination_location.setLatitude(geoCode.getFromLocationName(destination_input.getText().toString(), 1).get(0).getLatitude());
                        destination_location.setLatitude(geoCode.getFromLocationName(destination_input.getText().toString(), 1).get(0).getLongitude());
                        destination_location.set(destination_location);

                        float distance = source_location.distanceTo(destination_location)/1000;
                        System.out.println("Distance == " + distance);
                        kmVal = BigDecimal.valueOf(distance);
                        calculateFares();
                    } catch (IOException e) {
                        e.printStackTrace();
                    } catch (Exception e) {
                        e.printStackTrace();
                    } finally {
                        if (dialog!=null) {
                            dialog.dismiss();   
                        }
                    }
                }
            }).start();

我不知道为什么我的距离不对。我对我的代码有一个疑问,那就是我使用了 getFromLocationName 方法,并且我传递了 1 个参数以获得一个结果。这有什么区别吗?任何人有任何想法请帮忙。

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2 回答 2

1

谷歌地图为您提供道路距离,地理编码器为您提供乌鸦飞行的距离。

于 2012-09-03T08:34:25.277 回答
0

通过使用 Google Maps API 解决了这个问题。希望它会帮助其他人。它为您提供准确的距离。

final ProgressDialog dialog = ProgressDialog.show(AutoActivity.this, "", "Calculating...");

            new Thread(new Runnable() {
                @Override
                public void run() {
                    try {
                        float distance = 0.0f;
                        StringBuffer url = new StringBuffer("http://maps.googleapis.com/maps/api/directions/json?origin=");
                        url.append(source_input.getText().toString().replace(" ", "").trim().toString());
                        url.append("&destination=");
                        url.append(destination_input.getText().toString().replace(" ", "").trim().toString());
                        url.append("&sensor=false");

                        DefaultHttpClient httpClient = new DefaultHttpClient();
                        HttpGet httpGet = new HttpGet(url.toString());
                        HttpResponse httpResponse = httpClient.execute(httpGet);
                        HttpEntity httpEntity = httpResponse.getEntity();
                        String line = EntityUtils.toString(httpEntity);

                        JSONObject jsonObject = new JSONObject(line);
                        JSONArray jsonarray = jsonObject.getJSONArray("routes").getJSONObject(0).getJSONArray("legs");

                        for (int i = 0; i < jsonarray.length(); i++) {
                            JSONObject obj = jsonarray.getJSONObject(i);
                            distance  = Float.valueOf(obj.getJSONObject("distance").getString("text").replace("km", ""));
                            System.out.println("Distance == " + obj.getJSONObject("distance").getString("text").replace("km", ""));
                        }


                        kmVal = BigDecimal.valueOf(distance);
                        calculateFares();
                    } catch (IOException e) {
                        e.printStackTrace();
                    } catch (Exception e) {
                        e.printStackTrace();
                    } finally {
                        if (dialog!=null) {
                            dialog.dismiss();   
                        }
                    }
                }
            }).start();
于 2012-09-04T04:52:53.927 回答