1

因此，在我正在开发的应用程序中，我试图合并一个列表视图，以显示用户手机上的所有歌曲。我目前将它设置为显示所有音乐文件（如下面的代码所示），但我需要一种方法来过滤掉随机媒体文件中的实际歌曲（即录音或其他应用程序中使用的音频文件，如 facebook 或谷歌+）。我已经搜索并尝试了多种方法，但没有一种方法被证明是成功的。正如您在我的代码中看到的那样，我正在尝试获取歌曲的持续时间并确保它至少大约一分钟长。任何和所有的帮助将不胜感激！

谢谢，欧文

PS 只要问我是否需要查看更多我的代码，但我认为这应该足够了。

  private void init_phone_music_grid() {
    System.gc();
    String[] proj = { MediaStore.Audio.Media.DURATION,
            MediaStore.Audio.Media.DATA,
            MediaStore.Audio.Media.TITLE,
            MediaStore.Video.Media.ARTIST };

    musiccursor = managedQuery(MediaStore.Audio.Media.EXTERNAL_CONTENT_URI,
            proj, null, null, null);
    count = musiccursor.getCount();
    musiclist = (ListView) findViewById(R.id.lvTrackList);
    musiclist.setAdapter(new MusicAdapter(getApplicationContext()));

    musiclist.setOnItemClickListener(musicgridlistener);
    mMediaPlayer = new MediaPlayer();
}

private OnItemClickListener musicgridlistener = new OnItemClickListener() {
    public void onItemClick(AdapterView parent, View v, int position,
            long id) {
        System.gc();
        music_column_index = musiccursor
                .getColumnIndexOrThrow(MediaStore.Audio.Media.DATA);
        musiccursor.moveToPosition(position);
        String filename = musiccursor.getString(music_column_index);

        try {
            if (mMediaPlayer.isPlaying()) {
                mMediaPlayer.reset();
            }
            mMediaPlayer.setDataSource(filename);
            mMediaPlayer.prepare();
            mMediaPlayer.start();

            if(mMediaPlayer.isPlaying())
                chrono.start();

        } catch (Exception e) {

        }
    }
};

public class MusicAdapter extends BaseAdapter {
    private Context mContext;

    public MusicAdapter(Context c) {
        mContext = c;
    }

    public int getCount() {
        return count;
    }

    public Object getItem(int position) {
        return position;
    }

    public long getItemId(int position) {
        return position;
    }

    public View getView(int position, View convertView, ViewGroup parent) {

        System.gc();
        TextView tv = new TextView(mContext.getApplicationContext());
        String id = null;
        if (convertView == null) {
            long size = musiccursor.getColumnIndexOrThrow(MediaStore.Audio.Media.DURATION);

            if(size > 60000) {
            music_column_index = musiccursor
                    .getColumnIndexOrThrow(MediaStore.Audio.Media.TITLE);


            musiccursor.moveToPosition(position);
            id = musiccursor.getString(music_column_index);


            music_column_index = musiccursor
                    .getColumnIndexOrThrow(MediaStore.Audio.Media.DURATION);

            musiccursor.moveToPosition(position);
            if(!(musiccursor.getString(music_column_index).equalsIgnoreCase("<unknown>")))
                id += " - " + musiccursor.getString(music_column_index);

            tv.setText(id);
            }
        } else
            tv = (TextView) convertView;

        return tv;

    }
}
4

1 回答 1

4

使用以下查询获取持续时间超过 1 分钟的所有媒体

 musiccursor = managedQuery(MediaStore.Audio.Media.EXTERNAL_CONTENT_URI,
            proj, MediaStore.Audio.Media.DURATION + ">= 60000", null, null);
于 2012-09-03T06:30:27.033 回答