2

I want to create a Array with multidimension arrays from a database. The Database has 3 tables, one for vehicle, one for damages and one for damagesPhotos.

Table vehicle has two columns id and name

Table damages has four columns damagesID, vehicleID, damagesType and damagesDescription.

Table damagesPhotos has three columns damagesPhotoID, damagesID and damagesPhotoUrl

I need to combine thoose three columns into an array, that looks like this:

$vehicle = array( 
"id" => "somestring", 
"name" => "somestring", 
"damages" => array( 
    "damagesType" => "somestring", 
    "damagesDescription" => "somestring", 
    "photoOfDamages" => array( 
            "damagesPhotoUrl" => "somestring" 
    ) 
) 
);

I'am using this code:

$query = "SELECT * from vehicle v LEFT JOIN damages d ON v.id = d.vehicleID LEFT JOIN   damagesPhotos p ON d.damagesID = p.damagesID WHERE d.damagesID = p.damagesID AND v.id = 1";

$result = mysql_query($query);

$i = 0;
$vehicle = array();
while($row = mysql_fetch_array($result)){
    $vehicle[$i] = array( 
        "id" => $row[id], 
        "name" => $row[name], 
        "damages" => array( 
            "damagesType" => $row[damagesType], 
            "damagesDescription" => $row[damagesDescription], 
            "photoOfDamages" => array( 
                    "damagesPhotoUrl" => $row[damagesPhotoUrl] 
        ) 
        )
  );
  $i++;
  }

And it returns this:

  [{"vehilceId":"1",
  "name":"AW55005",
  "damages":{
        "damagesType":"Exterior",
        "damagesDescription":"Rust",
        "photoOfDamages":{
              "damagesPhotoUrl":"link to damagesPhoto 01"
        }
  }
  },

  {"vehilceId":"1",
  "name":"AW55005",
  "damages":{
        "damagesType":"Exterior",
        "damagesDescription":"Rust",
        "photoOfDamages":{
              "damagesPhotoUrl":"link to damagesPhoto 02"
  }
  }
  },

  {"vehilceId":"1",
  "name":"AW55005",
  "damages":{
        "damagesType":"Interior",
        "damagesDescription":"Scratch",
        "photoOfDamages":{
              "damagesPhotoUrl":"link to damagesPhoto 03"
        }
  }
  }

But as you can see the first two objects are the same only the damagesPhotoUrl is different. How do I merge thoose two array so it will look like this:

{"vehilceId":"1",
"name":"AW55005",
"damages":{
    "damagesType":"Exterior",
    "damagesDescription":"Rust",
    "photoOfDamages":{
        {"damagesPhotoUrl":"link to damagesPhoto 01"},
        {"damagesPhotoUrl":"link to damagesPhoto 02"}
    }
}
}, ...

Thanks in advance.

/ Morten

4

2 回答 2

1

理想情况下，我建议您将原始查询分成三个单独的查询并构建关联数组，首先处理来自“Vehicle”表的结果，然后使用“damages”表和来自“damagesPhotos”表的结果。

但是，如果您仍然只想进行一次查询，那么您就是这样做的，请注意我已经修改了代码以支持每辆车多次损坏和每次损坏一张以上的照片：

$query = "SELECT * from vehicle v LEFT JOIN damages d ON v.id = d.vehicleID LEFT JOIN   damagesPhotos p ON d.damagesID = p.damagesID WHERE d.damagesID = p.damagesID AND v.id = 1";

$result = mysql_query($query);

$i = 0;
$vehicle = array();
while($row = mysql_fetch_array($result)){
    $id = $row['id'];
    $damageId  = $row['damageId'];
    $damagesPhotoId = $row['damagesId'];

    if (!isset($vehicle[$id])) {
        $vehicle[$id] =  array(
            'id' => $id,
            'name' => $row['name'],
            'damages' => array(
            )
        )
    }
    if (!isset($vehicle[$id]['damages'][$damageId])) {
        $vehicle[$id]['damages'][$damageId] = array(
            'damagesType' => $row['damagesType'],
            'damageDescription' = $row['damageDescription'],
            'photoOfDamages' => array ()
        )
    }
    $vehicle[$id]['damages'][$damageId]['photoOfDamages'][] = array(
        'damagesPhotoUrl' => $row['damagesPhotoUrl']
    )
}
于 2012-09-02T17:22:43.013 回答
1

答案是你不能这样做：
你想要的是这样的：

"photoOfDamages":{
    {"damagesPhotoUrl":"link to damagesPhoto 01"},
    {"damagesPhotoUrl":"link to damagesPhoto 02"}
}

但是如果您尝试将具有相同键的值添加到关联数组，它将覆盖最后一个值，这意味着，如果您将创建：

"photoOfDamages":{
    {"damagesPhotoUrl":"link to damagesPhoto 01"}
}

并尝试添加：

{"damagesPhotoUrl":"link to damagesPhoto 02"}

结果将是：

"photoOfDamages":{
    {"damagesPhotoUrl":"link to damagesPhoto 02"}
}

为了解决这个问题，您需要做的是更改key连接运行计数器，例如：

"photoOfDamages":{
    {"damagesPhotoUrl-1":"link to damagesPhoto 01"},
    {"damagesPhotoUrl-2":"link to damagesPhoto 02"}
}

至于完成工作的代码，以下是一个示例 - 为了使其适合您，您应该取消注释，注释行并注释line with theforeach`
：

<?php

$rows = array(
    array(//vehicle 1 
            "id" => "somestring",
            "name" => "somestring",
            "damages" => array( 
                "damagesType" => "somestring", 
                "damagesDescription" => "somestring", 
                "photoOfDamages" => array( 
                            "damagesPhotoUrl" => "somestring1")
        )
    ),
     array(//vehicle 2
            "id" => "somestring",
            "name" => "somestring",
            "damages" => array( 
                "damagesType" => "somestring", 
                "damagesDescription" => "somestring", 
                "photoOfDamages" => array( 
                            "damagesPhotoUrl" => "somestring2")
        )
    )
);
$i = 0;
//$row = mysql_fetch_array($result);
//while($row){
foreach($rows as $row){ //this should be commented
    if($id === $row["id"]){
        $j++;
        $vehicle[$i]["damages"]["photoOfDamages"]["damagesPhotoUrl-$j"] = $row["damages"]["photoOfDamages"]["damagesPhotoUrl"];          
        continue;
    }
    $j = 1;
    $i++;
    $id = $row["id"];
    $vehicle[$i] = array( 
        "id" => $id, 
        "name" => $row[name], 
        "damages" => array( 
            "damagesType" => $row["damages"]["damagesType"], 
            "damagesDescription" => $row["damages"]["damagesDescription"], 
            "photoOfDamages" => array( 
                    "damagesPhotoUrl-$j" => $row["damages"]["photoOfDamages"]["damagesPhotoUrl"]  
            ) 
        )
  );
  //$row = mysql_fetch_array($result);      
}
print_r($vehicle);
?>

输出：

Array
(
    [1] => Array
        (
            [id] => somestring
            [name] => somestring
            [damages] => Array
                (
                    [damagesType] => somestring
                    [damagesDescription] => somestring
                    [photoOfDamages] => Array
                        (
                            [damagesPhotoUrl-1] => somestring1
                            [damagesPhotoUrl-2] => somestring2
                        )

                )

        )

)
于 2012-09-02T17:22:58.287 回答