(请参阅SQLFiddle以获得这篇文章的工作示例)
我有一张包含股票信息的表格,如下所示:
sp100_id _date bullishness agreement
----------------------------------------------
1 2011-03-16 1.01 0.33
1 2011-03-17 0.85 1.28
1 2011-03-18 0.89 1.25
1 2011-03-21 1.46 1.21
1 2011-03-22 0.39 2.53
2 2011-03-16 3.07 1.27
2 2011-03-17 2.09 0.80
2 2011-03-18 0.91 0.12
2 2011-03-21 1.50 0.00
2 2011-03-22 2.62 1.10
3 2011-03-16 0.73 1.13
3 2011-03-17 1.13 1.21
3 2011-03-18 1.12 0.45
3 2011-03-21 1.00 1.01
3 2011-03-22 1.00 0.53
4 2011-03-16 0.40 1.10
4 2011-03-17 2.40 0.03
4 2011-03-18 3.16 0.10
4 2011-03-21 0.86 0.50
4 2011-03-22 1.00 0.10
我需要将公司 ( sp100_id
) 按其平均bullishness
时间排序为前 3 名:
SELECT
sp100_id,
AVG(bullishness) as bullishness,
AVG(agreement) AS agreement
FROM stocks
WHERE _date BETWEEN '2011-03-16' AND '2011-03-22'
GROUP BY sp100_id LIMIT 3
这工作正常,因为结果是
SP100_ID BULLISHNESS AGREEMENT
2 2.038 0.658
4 1.564 0.366
3 0.996 0.866
现在我有了前 3 名,我需要按 升序对前 3 名进行重新排序AGREEMENT
:
SP100_ID BULLISHNESS AGREEMENT
4 1.564 0.366
2 2.038 0.658
3 0.996 0.866
这可能与一个查询有关吗?我尝试了以下但没有奏效。它仍然只订购bullishness
SELECT
sp100_id,
AVG(bullishness) as bullishness,
AVG(agreement) AS agreement
FROM stocks
WHERE _date BETWEEN '2011-03-16' AND '2011-03-22'
GROUP BY sp100_id
ORDER BY bullishness DESC, agreement ASC LIMIT 3
所以要明确:(1)我需要找到平均牛市度最高的前 3 名公司(2)这个前 3 名公司需要从最低到最高协议进行排序。最好用一个查询。你知道如何?