6

我在两个使用中间模型的模型之间建立了 M2M 关系。为了便于讨论,让我们使用手册中的示例:

class Person(models.Model):
    name = models.CharField(max_length=128)

    def __unicode__(self):
        return self.name

class Group(models.Model):
    name = models.CharField(max_length=128)
    members = models.ManyToManyField(Person, through='Membership')

    def __unicode__(self):
        return self.name

class Membership(models.Model):
    person = models.ForeignKey(Person)
    group = models.ForeignKey(Group)
    date_joined = models.DateField()
    invite_reason = models.CharField(max_length=64)

我想利用 Django 的基于类的视图,以避免编写 CRUD 处理视图。但是,如果我尝试使用默认的 CreateView,它就不起作用:

class GroupCreate(CreateView):
    model=Group

这会呈现一个包含 Group 对象上所有字段的表单,并为成员字段提供一个多选框,这对于简单的 M2M 关系是正确的。但是,没有办法指定 date_joined 或invite_reason,并且提交表单会出现以下 AttributeError:

“无法在指定中间模型的 ManyToManyField 上设置值。请改用 Membership 的 Manager。”

有没有一种巧妙的方法来覆盖通用 CreateView 的一部分,或者编写我自己的自定义视图来使用 mixins 来做到这一点?感觉这应该是框架的一部分,因为 Admin 界面使用内联自动处理与中间体的 M2M 关系。

4

5 回答 5

6

您必须扩展CreateView

from django.views.generic import CreateView

class GroupCreate(CreateView):
    model=Group

并覆盖form_valid()

from django.views.generic.edit import ModelFormMixin
from django.views.generic import CreateView

class GroupCreate(CreateView):
    model = Group

    def form_valid(self, form):
        self.object = form.save(commit=False)
        for person in form.cleaned_data['members']:
            membership = Membership()
            membership.group = self.object
            membership.person = person
            membership.save()
        return super(ModelFormMixin, self).form_valid(form)

正如文档所说,您必须为和membership之间的每个关系创建 new 。groupperson

我在这里看到了form_valid覆盖: Using class-based UpdateView on a mtm with an intermediary model

于 2013-04-01T14:48:54.967 回答
2
class GroupCreate(CreateView):
    model = Group

    def form_valid(self, form):
        self.object = form.save(commit=False)

        ### delete current mappings
        Membership.objects.filter(group=self.object).delete()

        ### find or create (find if using soft delete)
        for member in form.cleaned_data['members']:
            x, created = Membership.objects.get_or_create(group=self.object, person=member)
            x.group = self.object
            x.person = member
            #x.alive = True # if using soft delete
            x.save()
        return super(ModelFormMixin, self).form_valid(form)
于 2015-07-29T16:43:21.513 回答
0

就在几天前,我面临着同样的问题。Django 在处理中间 m2m 关系方面存在问题。

这是我发现有用的解决方案:

1. Define new CreateView
class GroupCreateView(CreateView):
    form_class = GroupCreateForm
    model = Group
    template_name = 'forms/group_add.html'
    success_url = '/thanks'

然后更改已定义表单的保存方法 - GroupCreateForm。Save 负责将更改永久保存到 DB。我无法仅通过 ORM 完成这项工作,因此我也使用了原始 SQL:

1. Define new CreateView
class GroupCreateView(CreateView):


class GroupCreateForm(ModelForm):
    def save(self):
        # get data from the form
        data = self.cleaned_data
        cursor = connection.cursor()
        # use raw SQL to insert the object (in your case Group)
        cursor.execute("""INSERT INTO group(group_id, name)
                          VALUES (%s, %s);""" (data['group_id'],data['name'],))
        #commit changes to DB
        transaction.commit_unless_managed()
        # create m2m relationships (using classical object approach)
        new_group = get_object_or_404(Group, klient_id = data['group_id'])
        #for each relationship create new object in m2m entity
        for el in data['members']:
            Membership.objects.create(group = new_group, membership = el)
        # return an object Group, not boolean!
        return new_group

注意:我已经稍微改变了模型,如你所见(我有自己独特的 IntegerField 作为主键,不使用序列号。这就是它进入的方式get_object_or_404

于 2012-12-20T11:58:00.963 回答
0

'作为参考,我最终没有使用基于类的视图,而是做了这样的事情:

def group_create(request):
    group_form = GroupForm(request.POST or None)
    if request.POST and group_form.is_valid():
        group = group_form.save(commit=False)
        membership_formset = MembershipFormSet(request.POST, instance=group)
        if membership_formset.is_valid():
            group.save()
            membership_formset.save()
            return redirect('success_page.html')
    else:
        # Instantiate formset with POST data if this was a POST with an invalid from,
        # or with no bound data (use existing) if this is a GET request for the edit page.
        membership_formset = MembershipFormSet(request.POST or None, instance=Group())

    return render_to_response(
        'group_create.html',
        {
            'group_form': recipe_form,
            'membership_formset': membership_formset,
        },
        context_instance=RequestContext(request),
    )

这可能是基于类的实现的起点,但它很简单,不值得我花时间尝试将它硬塞到基于类的范例中。

于 2012-12-22T04:39:32.843 回答
0

只有一条评论,当使用 CBV 时,您需要使用 commit=True 保存表单,因此创建组并提供可用于创建成员资格的 id。否则,commit=False 时,组对象还没有 id 并出现错误。

于 2013-12-09T19:21:07.943 回答