2

我正在尝试编写一个程序来接受受害者及其人数。victims 参数将包含这样的值'123,321,222'，我正在使用函数调用SPLIT_STR_FUNCTION将文本拆分为逗号分隔值。然后我将在数据库中插入每个值。

这是我的程序：

CREATE DEFINER=`root`@`localhost` PROCEDURE `InsertPost`( in pmsg text, in pthumbPath text, in ppath text, in puserid bigint, in count int, in victims text) 
BEGIN 
INSERT INTO posts(path,thumbpath,msg,userid) VALUES(ppath,pthumbpath,pmsg,puserid);


SET @lastpostid = (SELECT postid FROM posts ORDER BY postid DESC LIMIT 1);

SET @startindex=1;

WHILE @startindex <= count DO 
SET @IndividualIDs=convert((select SPLIT_STR_Function(victims, ',', @startindex)),signed); 
SET @startindex=startindex+1;     
INSERT INTO victims(victimid,postid) VALUES(@IndividualIDs,@lastpostid); 

end WHILE; 
END

错误： 字段列表中的未知列 startindex

SPLIT_STR_FUNCTION：（从这里）

CREATE DEFINER=`root`@`localhost` FUNCTION `SPLIT_STR_Function`(
x VARCHAR(255),
delim VARCHAR(12),
pos INT
 ) 

 RETURNS varchar(255) CHARSET latin1
 RETURN REPLACE(SUBSTRING(SUBSTRING_INDEX(x, delim, pos),
    LENGTH(SUBSTRING_INDEX(x, delim, pos -1)) + 1),
    delim, '')
4

1 回答 1

1

当您增加它时，您的用户变量@startindex会丢失：@

SET @startindex=startindex+1;
-- Should be:
SET @startindex = @startindex+1;
于 2012-08-31T13:24:29.183 回答