我做了一个函数,它返回显示的分页数字。我想得到这样的东西(括号是唯一显示活动站点的地方):
如果页面 < 10
1 2 3 4 5 6 7 8 9 10
如果页面 > 10
1 2 3 ... 20 [30] 40 ... 78 79 80
其中 [30] 是活动页面。如果活动页面 < 3
1 2 [3] 4 ... 20 30 40 ... 78 79 80
等我的代码:
count_all - number of all items
items_on_page - items displayed on one page
page - current page
countpages = int(float(count_all+(items_on_page-1))/float(items_on_page))
linkitems = 10
if countpages > (linkitems-1):
countpagesstr = list()
for i in range(1,int(float(linkitems+(2))/float(3))):
countpagesstr += [str(i)]
countpagesstr += ['...']
sr = int(countpages/2)
for i in range(sr-1, sr+1):
countpagesstr += [str(i)]
countpagesstr += ['...']
for i in range(countpages-3, countpages):
countpagesstr += [str(i)]
else:
cp = list()
for c in range(1,countpages+1):
cp.append(str(c))
countpagesstr = cp
return countpagesstr
如何做得更好?