我有一个相当简单的集合:
var Access = new Schema({
userId : { type: ObjectId, index: true },
token : { type: String, index: true },
isOwner : { type: Boolean, index: true },
});
mongoose.model('Access', Access);
var Workspace = new Schema({
name : { type: String, lowercase: true, unique: true},
description : String,
isActive : Boolean,
settings : {
longName : String,
welcomeMessage : String,
countryId : { type: ObjectId, index: true },
},
access : [ Access ],
});
mongoose.model('Workspace', Workspace);
当用户连接时,我有一个中间件检查令牌并查看是否一切正常。所以我有:
exports.tokenCall = function( req, res, next, token ){
var Workspace = mongoose.model('Workspace'),
User = mongoose.model('User'),
accessEntry;
req.application = {};
// Find the token
Workspace.findOne({ 'access.token': token } , function(err, doc){
if(err){
next( new g.errors.RuntimeError503( err ) );
} else {
if(! doc ){
next( new g.errors.BadtokenError403() );
} else {
accessEntry = doc.access.filter(function(entry){ return entry.token == token; } )[0];
req.application.workspaceId = doc._id;
req.application.workspaceName = doc.name;
req.application.userId = accessEntry.userId;
req.application.login = accessEntry.login;
req.application.token = token;
req.application.workspace = doc; // Contains all of the settings!
next();
}
}
});
}
我相信您可以在这里看到我的问题:我运行Workspace.findOne({ 'access.token': token } , function(err, doc){
以找到具有正确标记的文档。但是,然后,我实际上...搜索一个数组(!)以找到我寻找的实际令牌!accessEntry = doc.access.filter(function(entry){ return entry.token == token; } )[0];
我确信这不是这样做的方法——当然。如果我向下查询 4 级怎么办...?!?
那么,这样做的正确方法是什么?