0

我在这种格式的文本文件中有一个列表。该列表有 1000 个这样的条目，这是一个小样本。

myitems =[
      ['some text, A', '12345'],
      ['place name 1', 'AAA'],
      ['some text, A', '12345'],
      ['some text', '12345'],
      ['some text CC', 'wwww'],
      ['new text', '12345'],
      ['other text, A', '12345'],
    ]

我如何从文本文件中读取列表并获得这样的输出。

newItems = [
  ['12345', 'some text, A'],
  ['AAA', 'place name 1'],
  ['12345', 'some text, A'],
  ['12345', 'some text'],
  ['wwww', 'some text CC'],
  ['12345', 'new text'],
  ['12345', 'other text, A'],
]

我能够从文件中读取并将其作为字符串进行操作，但我如何将其作为列表获取。不能以逗号分隔，因为单个列表项可能有逗号。

4

6 回答 6

5

最简单的是列表理解：

new_items = [i[::-1] for i in myitems]
于 2012-08-30T23:19:44.410 回答
3 
 newItems = [[b, a] for a, b in myitems]
于 2012-08-30T23:29:31.750 回答
1 
import sys

# Reading your file (the path has been passed in argument) and storing each lines in the array called "input"
input = []
with open(sys.argv[1], 'r') as all_lines:
    for line in all_lines:
        if line:
            input.append(line)

# Creating your array "newItems"
for j in input: 
    print j

newItems = []
if len(input)>2:
    for i in range(1, len(input)-1):
        # Getting content inside brackets. Ex: {{ 'some text, A', '12345' }}
        my_str = input[i].split("[")[1].split("]")[0]
        my_elements = my_str.split("'")

        # Appending elements
        newItems.append([my_elements[1], my_elements[3]])

print  newItems
于 2012-08-30T23:31:33.040 回答
0

要读取文件，请使用 CSV，因为您声明“个别项目可能有逗号”

例子：

如果您的文件实际上如下所示：

'some text, A','12345'
'place name 1','AAA'
'some text, A','12345' 
'some text','12345'
'some text CC','wwww' 
'new text','12345'
'other text, A','12345'

然后此代码读取 csv 文件并反转字段：

import csv

with open('test.csv','rb') as csvIN:
    for row in csv.reader(csvIN, delimiter=',',quotechar="'"):
        print row
        row=row[::-1]
        print '==>',row,'\n'

印刷：

['some text, A', '12345']
==> ['12345', 'some text, A'] 

['place name 1', 'AAA']
==> ['AAA', 'place name 1'] 

['some text, A', '12345 ']
==> ['12345 ', 'some text, A'] 

['some text', '12345']
==> ['12345', 'some text'] 

['some text CC', 'wwww ']
==> ['wwww ', 'some text CC'] 

['new text', '12345']
==> ['12345', 'new text'] 

['other text, A', '12345']
==> ['12345', 'other text, A']
于 2012-08-31T01:13:06.233 回答
0

如果它真的看起来像那样

 with open(my_file) as f:
   exec(f.read()) #read in the text and evaluate it in python creating myitems variable
   my_list = [reversed(l) for l in myitems]

exec 非常危险，很可能不应该使用......但这应该可以

更好的解决方案

 #name yourfile with the myitems = [...] to items.py
 import items
 new_items = [reversed(l) for l in items.myitems]
于 2012-08-30T23:16:50.547 回答
0 
import re

f = open('myfile.txt', 'r')
newItems = []
for line in f:
    foo = re.search("\'(.*)\'.*\'(.*)\'", line) #we assume the values are 
                                                #in single quotes
    if foo is not None:
        a, b = foo.groups()
        newItems.append([b, a])
于 2012-08-30T23:39:53.187 回答