31

Suppose I have an arbitrary set of files included in the Main App Bundle. I would like to fetch the file URLs for those at launch and store them somewhere. Is this possible using NSFileManager? The documentation is unclear in that regard.

Note: I only need the file URLs, I do not need to access the actual files.

4

4 回答 4

68

You can get the URL of a file in the main bundle using

NSString *path = [[NSBundle mainBundle] pathForResource:@"SomeFile" ofType:@"jpeg"];
NSURL *url = [NSURL fileURLWithPath:path];

You can write this URL to, for example, a property list file in the Documents directory:

NSString *docsDir = [NSSearchForDirectoriesInDomains(NSDocumentsDirectory, NSUserDomainMask, YES) objectAtIndex:0];
NSString *plistPath = [docsDir stringByAppendingPathComponent:@"Files.plist"];
NSDictionary *dict = [NSDictionary dictionaryWithObjectsAndKeys:[url absoluteString] forKey:@"SomeFile.jpeg"];
[dict writeToFile:plistPath atomically:YES];

If you don't know the names of the files and you just want to list all the files in the bundle, use

NSArray *files = [[NSFileManager defaultManager] contentsOfDirectoryAtPath:[[NSBundle mainBundle] bundlePath] error:NULL];
for (NSString *fileName in files) {
    NSString *path = [[NSBundle mainBundle] pathForResource:fileName ofType:nil];
    NSURL *url = [NSURL fileURLWithPath:path];
    // do something with `url`
}
于 2012-08-30T21:34:24.200 回答
6

Or in Swift 4:

        let url = Bundle.main.url(forResource: "FileName", withExtension: ".xyz")
于 2018-03-17T10:25:21.663 回答
3

Yes, you would get their path:

NSString *path = [NSBundle mainBundle] pathForResource:@"file1" ofType:@"png"];
NSURL *fileURL = [NSURL fileURLWithPath:path]

// save it as any other object or in a dictionary:

[myMutableDictionary setObject:fileURL forKey:@"file1.png"];

EDIT: to get the complete list of files, use the NSFileManager, get the path to the bundle itself, then walk each directory getting the files, making URLs, and saving them somewhere. There is oodles of code on SO how to walk a directory to do this. [You should update your question to be more specific on what you want, this was not made clear at all originally]

于 2012-08-30T21:34:16.090 回答
1

There's an API on NSBundle (documentation) available on 10.6 or iOS 4 to get an NSURL directly, rather than passing a path to the NSURL constructor:

- (NSURL *)URLForResource:(NSString *)name withExtension:(NSString *)ext;

It also has variants that take a subdirectory and localizationName, the same as its -pathForResource: equivalents.

于 2014-08-04T18:08:05.713 回答