4

我想拆分一个数组:

$o = json_decode('[{"id":"1","color":"green"},{"id":"2","color":"green"},{"id":"3","color":"yellow"},{"id":"4","color":"green"}]');

根据每个item的颜色属性,填充对应的子数组

$a = array("green", "yellow", "blue");

function isGreen($var){
    return($var->color == "green");
}

$greens = array_filter($o, "isGreen");
$yellows = array_filter($o, "isYellow");
// and all possible categories in $a..

my$a的长度 > 20,并且可以增加更多,所以我需要一种通用的方法而不是手动编写函数

似乎不存在一个函数 array_split 来生成所有过滤的数组
,否则我可能需要一种 lambda 函数

4

3 回答 3

6

您可以执行以下操作:

$o = json_decode('[{"id":"1","color":"green"},{"id":"2","color":"green"},{"id":"3","color":"yellow"},{"id":"4","color":"green"}]');

$greens = array_filter($o, function($item) {
    if ($item->color == 'green') {
        return true;
    }

    return false;
});

或者,如果您想创建一些真正通用的东西,您可以执行以下操作:

function filterArray($array, $type, $value)
{
    $result = array();
    foreach($array as $item) {
        if ($item->{$type} == $value) {
            $result[] = $item;
        }
    }

    return $result;
}

$o = json_decode('[{"id":"1","color":"green"},{"id":"2","color":"green"},{"id":"3","color":"yellow"},{"id":"4","color":"green"}]');
$greens = filterArray($o, 'color', 'green');
$yellows = filterArray($o, 'color', 'yellow');

在我的第二个示例中,您可以只传递数组并告诉函数根据什么值过滤(例如颜色或其他一些未来属性)。

请注意,我没有做任何错误检查属性是否真的存在

于 2012-08-30T21:00:10.127 回答
1

我不会走上手动或动态创建大量函数的道路。

这是我的想法,并且可以修改设计以使过滤器可以链接:

<?php
class ItemsFilter
{
    protected $items = array();

    public function __construct($items) {
        $this->items = $items;
    }

    public function byColor($color)
    {
        $items = array();

        foreach ($this->items as $item) {
            // I don't like this: I would prefer each item was an object and had getColor()
            if (empty($item->color) || $item->color != $color)
                continue;

            $items[] = $item;
        }

        return $items;
    }
}

$items = json_decode('[{"id":"1","color":"green"},{"id":"2","color":"green"},{"id":"3","color":"yellow"},{"id":"4","color":"green"}]');
$filter = new ItemsFilter($items);
$greens = $filter->byColor('green');

echo '<pre>';
print_r($greens);
echo '</pre>';
于 2012-08-30T20:59:45.213 回答
0

如果您需要更多参数,可以使用此函数:

function splitArray($array, $params) {
    $result = array();

    foreach ($array as $item) {

        $status = true;

        foreach ($params as $key => $value) {
            if ($item[$key] != $value) {
                $status = false;
                continue;
            }
        }

        if ($status == true) {
            $result[] = $item;
        }
    }

    return $result;
}

$greensAndID1 = splitArray($o, array('color' => 'green', 'id' => 1));
于 2015-03-22T23:22:05.390 回答