8

我正在尝试从我的 python 脚本向 Mountain Lion 发送通知，并对点击通知做出反应。现在可以完美地找到发送通知。但是我无法让 Lion 在单击时回调我的脚本。

这就是我所做的。我实现了一个通知类。该类实例的唯一目的是通过调用来提供通知notify()。在相同的方法中，我将对象设置为应用程序的委托。

import Foundation
import objc
import AppKit

class MountainLionNotification(Foundation.NSObject, Notification):

    def notify(self, title, subtitle, text, url):
        NSUserNotification = objc.lookUpClass('NSUserNotification')
        NSUserNotificationCenter = objc.lookUpClass('NSUserNotificationCenter')
        notification = NSUserNotification.alloc().init()
        notification.setTitle_(str(title))
        notification.setSubtitle_(str(subtitle))
        notification.setInformativeText_(str(text))
        notification.setSoundName_("NSUserNotificationDefaultSoundName")
        notification.setUserInfo_({"action":"open_url", "value":url})
        AppKit.NSApplication.sharedApplication().setDelegate_(self)
        NSUserNotificationCenter.defaultUserNotificationCenter().scheduleNotification_(notification)

    def applicationDidFinishLaunching_(self, sender):
        userInfo = sender.userInfo()
        if userInfo["action"] == "open_url":
            import subprocess
            subprocess.Popen(['open', userInfo["value"]])

现在，我希望applicationDidFinishLaunching_()在单击通知时被呼叫。不幸的是，这永远不会发生。我究竟做错了什么？

4

1 回答 1

8

好的，找到了。没跑AppHelper.runEventLoop()。很明显是面相错误。以下代码有效：

class MountainLionNotification(Foundation.NSObject, Notification):

    def notify(self, title, subtitle, text, url):
        NSUserNotification = objc.lookUpClass('NSUserNotification')
        NSUserNotificationCenter = objc.lookUpClass('NSUserNotificationCenter')
        notification = NSUserNotification.alloc().init()
        notification.setTitle_(str(title))
        notification.setSubtitle_(str(subtitle))
        notification.setInformativeText_(str(text))
        notification.setSoundName_("NSUserNotificationDefaultSoundName")
        notification.setHasActionButton_(True)
        notification.setOtherButtonTitle_("View")
        notification.setUserInfo_({"action":"open_url", "value":url})
        NSUserNotificationCenter.defaultUserNotificationCenter().setDelegate_(self)
        NSUserNotificationCenter.defaultUserNotificationCenter().scheduleNotification_(notification)

    def userNotificationCenter_didActivateNotification_(self, center, notification):
        userInfo = notification.userInfo()
        if userInfo["action"] == "open_url":
            import subprocess
            subprocess.Popen(['open', userInfo["value"]])
于 2012-08-31T08:53:36.997 回答