java - 按位运算，如何检查 0 或 1？

Question

我有一个整数，如：

0x10000010

我想知道某个特定位是 1 还是 0。例如，类似：

int number = 0x10000010;
for (int i = 0; i < 8; i++) {
    if (ith bit == 1) {
        System.out.println("bit " + i + " is 1.");
    } else {
        System.out.println("bit " + i + " is 0.");
    }
}

---- output ----
bit 0 is 1
bit 1 is 0
bit 2 is 0
bit 3 is 0
bit 4 is 0
bit 5 is 0
bit 6 is 1
bit 7 is 0

我忘了怎么做，这种操作叫什么，

谢谢

Answer 1

number & (1 << i)如果该位未设置，则为 0，如果已设置，则为非零。

Answer 2

类似于 dty 的回答

int number = 0b10000010; // you are assuming this is binary not hex.
for (int i = 0; i < 8; i++) {
    if((number >> i) & 1 != 0)
        System.out.println("bit " + i + " is 1.");
     else 
        System.out.println("bit " + i + " is 0.");
}

或者

int number = 0b10000010; // you are assuming this is binary not hex.
for (int i = 0; i < 8; i++) 
    System.out.println("bit " + i + " is " + ((number >> i) & 1));