我正在尝试使用列表限制我的模型形式外键实例:
这是我的模型:
class Voicemail(models.Model):
internalline = models.ForeignKey(InternalLine)
person = models.ForeignKey(Person)
然后在相应模型形式的 init 方法中,我有
class VoicemailForm(ModelForm):
def __init__(self, *args, **kwargs):
....
....
# self.fields['internalline'].queryset = self.person.getPersonLines() # this throws error in template.
self.fields['internalline'].queryset = self.person.line.all()
print(self.person.getPersonLines())
print(self.person.line.all())
这两个打印打印相同的输出:
[<InternalLine: 1111>, <InternalLine: 5555>]
[<InternalLine: 1111>, <InternalLine: 5555>]
在 getPersonLines 中,我做了一些额外的逻辑并返回一个行列表:
def getPersonLines(self):
lines = []
for line in self.line.order_by('extension'):
lines.append(line)
for phone in self.phonesst_set.all():
for line in phone.line.order_by('extension'):
if line not in lines:
lines.append(line)
return lines
现在,当我尝试在模板中渲染时,如果我使用 getPersonLines 返回的列表,我会得到错误,
Caught AttributeError while rendering: 'list' object has no attribute 'all'
但是,如果我使用 self.person.line.all(). 填充查询集,同样的事情会起作用。
尝试使用列表填充我的查询集时,我是否遗漏了什么?
提前致谢!!
更新
这是堆栈跟踪
self.fields['internalline'].choices = self.person.getPersonLines()
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "C:\Python26\lib\site-packages\django\utils\encoding.py", line 27, in __str__
return self.__unicode__().encode('utf-8')
File "C:\Python26\lib\site-packages\django\forms\forms.py", line 95, in __unicode__
return self.as_table()
File "C:\Python26\lib\site-packages\django\forms\forms.py", line 217, in as_table
errors_on_separate_row = False)
File "C:\Python26\lib\site-packages\django\forms\forms.py", line 180, in _html_output
'field': unicode(bf),
File "C:\Python26\lib\site-packages\django\forms\forms.py", line 408, in __unicode__
return self.as_widget()
File "C:\Python26\lib\site-packages\django\forms\forms.py", line 439, in as_widget
return widget.render(name, self.value(), attrs=attrs)
File "C:\Python26\lib\site-packages\django\forms\widgets.py", line 516, in render
options = self.render_options(choices, [value])
File "C:\Python26\lib\site-packages\django\forms\widgets.py", line 533, in render_options
for option_value, option_label in chain(self.choices, choices):
TypeError: 'InternalLine' object is not iterable
更新 2:
这是整个__init__
方法
class VoicemailForm(ModelForm):
def __init__(self, *args, **kwargs):
try:
self.person = kwargs.pop('person', None)
super(VoicemailForm, self).__init__(*args, **kwargs)
for field in self.fields:
self.fields[field].widget.attrs['class'] = 'required_field'
print(self.person.getPersonLines())
print(self.person.line.all())
if self.person:
self.fields['internalline'].choices = self.person.getPersonLines()
#self.fields['internalline'].queryset = self.person.line.all()
except Exception as e:
print("Error overwriting __init__ of VoicemailForm")
print(e)
这就是我如何称呼我的表格
voicemail = VoicemailForm(person=person, prefix='voicemail')
更新 3 我尝试创建一个 django 表单,如下所示:
class test(forms.Form):
line = forms.ChoiceField()
def __init__(self, *args, **kwargs):
super(test, self).__init__(*args, **kwargs)
self.fields['line'].choices=person.getPersonLines()
但我继续得到同样的错误
for option_value, option_label in chain(self.choices, choices):
TypeError: 'InternalLineSST' object is not iterable
然后我厌倦了这样的事情:
test = [1,2,3]
class myform(forms.Form):
line = forms.ChoiceField()
def __init__(self, *args, **kwargs):
super(myform, self).__init__(*args, **kwargs)
self.fields['line'].choices = test
>>> form = myform()
>>>print(form)
which gives me a similar error
File "C:\Python26\lib\site-packages\django\forms\forms.py", line 439, in as_widget
return widget.render(name, self.value(), attrs=attrs)
File "C:\Python26\lib\site-packages\django\forms\widgets.py", line 516, in render
options = self.render_options(choices, [value])
File "C:\Python26\lib\site-packages\django\forms\widgets.py", line 533,in render_options
for option_value, option_label in chain(self.choices, choices):
TypeError: 'int' object is not iterable`
Am I missing something here?