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我有一个 Table tempslotsassignedfordept如下 

DEPT        ScheduledStartDate          ScheduledEndDate            TotalSlots

DevEng      2012-07-17 00:00:00.000     2012-08-28 00:00:00.000     39
DevEng      2012-07-17 00:00:00.000     2012-08-31 00:00:00.000     18
DevEng      2012-07-18 00:00:00.000     2012-08-29 00:00:00.000     9
DevEng      2012-07-19 00:00:00.000     2012-08-30 00:00:00.000     40
Prod        2012-07-19 00:00:00.000     2012-08-30 00:00:00.000     8
Rel         2012-07-19 00:00:00.000     2012-08-30 00:00:00.000     19
Rel         2012-07-19 00:00:00.000     2013-08-15 00:00:00.000     1

我必须捕获每个部门的总时隙的上述总和。如果一个部门存在连续 3 天。
如果您看到上表，则有部门 deveng 有连续三个预定开始日期为 2012-07-17、2012-07-18、2012-07-19。

我正在尝试通过使用以下查询来查看结果，请您帮忙查看更多实现以查看确切结果吗？ 

SELECT  Tmain.DepartmentCode, 
                CONVERT(VARCHAR(20), Tmain.ScheduledStartDate, 101) 'ScheduledStartDate',
                SUM(Tmain.TotalSlots) 'Tmain.TotalSlots',T1Sub.TotalSlots 'T1SubTotalSlots', T2Sub.TotalSlots 'T2SubTotalSlots'

                FROM    tempSlotsAssignedForDept Tmain

                        INNER   JOIN (Select    DATEADD(DAY,1,T1.ScheduledStartDate) 'ScheduledStartDate',SUM(T1.TotalSlots) 'TotalSlots'
                                        FROM    tempSlotsAssignedForDept  T1 
                                                INNER JOIN tempSlotsAssignedForDept Tmain                    
                                                ON (T1.ScheduledStartDate = dateadd(day, -1, tmain.ScheduledStartDate ) and  
                                                    T1.DepartmentCode = tmain.DepartmentCode)
                                                GROUP BY T1.ScheduledStartDate ) T1Sub                        
                        ON Tmain.ScheduledStartDate = T1Sub.ScheduledStartDate

                        INNER   JOIN (Select    DATEADD(DAY,2,T2.ScheduledStartDate) 'ScheduledStartDate',SUM(T2.TotalSlots) 'TotalSlots'
                                        FROM    tempSlotsAssignedForDept  T2 
                                                INNER JOIN tempSlotsAssignedForDept Tmain                    
                                                ON (T2.ScheduledStartDate = dateadd(day, -2, tmain.ScheduledStartDate ) and  
                                                    T2.DepartmentCode = tmain.DepartmentCode)
                                                GROUP BY T2.ScheduledStartDate ) T2Sub                
                        ON Tmain.ScheduledStartDate = T2Sub.ScheduledStartDate

                GROUP BY    Tmain.DepartmentCode,Tmain.ScheduledStartDate,T1Sub.TotalSlots , T2Sub.TotalSlots 
                ORDER BY Tmain.ScheduledStartDate

上面的查询是 

DepartmentCode  ScheduledStartDate  Tmain.TotalSlots    T1SubTotalSlots T2SubTotalSlots
DevEng          07/19/2012          40                  9               57
Prod            07/19/2012          8                   9               57
Rel             07/19/2012          20                  9               57

最终结果应如下所示。
因为部门 prod 和 rel 没有 3 天的 schedulestartdate 系列 

DepartmentCode  ScheduledStartDate  Tmain.TotalSlots    T1SubTotalSlots T2SubTotalSlots
DevEng          07/19/2012          40                  9               57

请帮忙。

4

1 回答 1

1

这是您正在寻找的答案：

Select * from 
(
Select DepartmentCode,ScheduledStartDate,[Tmain.TotalSlots]
,(Select SUM(T1.TotalSlots) from tempSlotsAssignedForDept  T1 where t1.departmentCode=a.DepartmentCode
and T1.ScheduledStartDate = dateadd(day, -1, a.ScheduledStartDate )) T1SubTotalSlots 
,(Select SUM(T1.TotalSlots) from tempSlotsAssignedForDept  T1 where t1.departmentCode=a.DepartmentCode
and T1.ScheduledStartDate = dateadd(day, -2, a.ScheduledStartDate )) T2SubTotalSlots 
from 
(
SELECT  Tmain.DepartmentCode, 
CONVERT(VARCHAR(20), Tmain.ScheduledStartDate, 101) ScheduledStartDate,
SUM(Tmain.TotalSlots) 'Tmain.TotalSlots'
--,(Select SUM(T1.TotalSlots) from tempSlotsAssignedForDept t1 where t1.DepartmentCode=tmain.departmentcode 
--and T1.ScheduledStartDate = dateadd(day, -1, tmain.ScheduledStartDate ))
FROM    tempSlotsAssignedForDept Tmain
GROUP BY    Tmain.DepartmentCode,Tmain.ScheduledStartDate
) a) b where [Tmain.TotalSlots] is not null and T1SubTotalSlots is not null and T2SubTotalSlots is not null
于 2012-08-30T15:42:59.513 回答