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我有这个联系

    <?php
    $db_host = 'localhost';
    $db_user = 'root';
    $db_pass = '';
    $db_name = 'databasename';
    $conn = mysql_connect($db_host,$db_user,$db_pass) or die(mysql_error());
    mysql_select_db($db_name,$conn);
    mysql_query("SET NAMES 'utf8'");
    mysql_query('SET CHARACTER SET utf8');
    ?>

但我的旧连接不适用于此代码

        //connect to database
$link = mysqli_connect('localhost','root','');
mysqli_select_db($link,'databasename');
//get all rows
$query = mysqli_query($link,'SELECT * FROM categories');
while ( $row = mysqli_fetch_assoc($query) )
{
    $menu_array[$row['catid']] = array('catname' => $row['catname'],'parentid' => $row['parentid']);
    $menu_array[$row['catid']] = array('catname' => $row['catname'],'parentid' => $row['parentid'],'catid'=>$row['catid']);
}
//recursive function that prints categories as a nested html unorderd list
function generate_menu($parent)
{
$has_childs = false;
//this prevents printing 'ul' if we don't have subcategories for this category
global $menu_array;
    //use global array variable instead of a local variable to lower stack memory requierment
    foreach($menu_array as $key => $value)
    {
        if ($value['parentid'] == $parent)
        {
            //if this is the first child print '<ul>'
            if ($has_childs === false)
            {
                //don't print '<ul>' multiple times
                $has_childs = true;
                echo '<ul>';
            }
            echo '<li><a href="category.php?catid='. $value['catid'] . '">' . $value['catname'] . '</a>';

我认为我的错误位于这段代码之间.. 最后我只需将 mysqli_connect 替换为 mysql_connect 没有我

while ( $row = mysqli_fetch_assoc($query) )
{
    $menu_array[$row['catid']] = array('catname' => $row['catname'],'parentid' => $row['parentid']);
}
4

1 回答 1

2

您应该考虑使用 mysqli_connect 和 mysqli_select_db。

也改为$query = mysqli_query($link,'SELECT * FROM categories');：

$query = mysqli_query($link,'SELECT * FROM `categories`');

我认为问题可能出在连接上，其他一切看起来都很好，我认为您无法使用正常的 mysql_conn 访问 mysqli 对象。

试一试

另外，不要改成mysql，现在太旧了！看看mysqli和php 数据对象都有很好的文档记录

于 2012-08-30T15:45:16.300 回答