php - DateTime 未将字符串解析为日期

Question

我正在使用 DateTime 构造函数来构造日期，但它没有解析，我的代码如下

  $current=$timeDate->nowDate(); 

//$timeDate->nowDate() is sugarCRM function returns date and in next line i fetched variables $y, $m, $d successfully 

  list($y, $m, $d) = explode("/", $current);
  $expiredate = new DateTime($y.'-'.$m.'-'.$d);

在异常中捕获以下错误

DateTime::__construct() [datetime.--construct]: Failed to parse time string (08-30-2012) at position 0 (0): Unexpected character

Answer 1

变量（$y，$m，$d）的顺序似乎是关闭的，你应该写

list($m, $d, $y) = explode("/", $current);

Answer 2

如果您正在寻找更直接的方法，您可以使用：

$current = new DateTime('now');
$expiredate = $current->format('Y-m-d');