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我在 Solaris 11 X86 中运行 Eclipse 3.7.2。它随机挂起（每隔几个小时或每隔几分钟）。当它挂起时，我做了一个线程转储，它表明Main线程处于定时等待状态。Eclipse 永远不会从睡眠状态中醒来并且变得无响应，我必须重新启动 Eclipse 才能再次使用它。

主线程正在休眠，因为：

org.eclipse.swt.widgets.Control.dragDetect

是否有任何已知的解决此问题的方法？

编辑：

操作系统

SunOS solaris 5.11 11.0 i86pc i386 i86pc Solaris

完整的堆栈跟踪：

"main" prio=3 tid=0x080e8400 nid=0x1 waiting on condition [0x08045000]
   java.lang.Thread.State: TIMED_WAITING (sleeping)
    at java.lang.Thread.sleep(Native Method)
    at org.eclipse.swt.widgets.Control.dragDetect(Control.java:2204)
    at org.eclipse.swt.widgets.Tree.dragDetect(Tree.java:1125)
    at org.eclipse.swt.widgets.Control.gtk_button_press_event(Control.java:2791)
    at org.eclipse.swt.widgets.Control.gtk_button_press_event(Control.java:2759)
    at org.eclipse.swt.widgets.Composite.gtk_button_press_event(Composite.java:681)
    at org.eclipse.swt.widgets.Tree.gtk_button_press_event(Tree.java:1871)
    at org.eclipse.swt.widgets.Widget.windowProc(Widget.java:1731)
    at org.eclipse.swt.widgets.Control.windowProc(Control.java:5016)
    at org.eclipse.swt.widgets.Tree.windowProc(Tree.java:3530)
    at org.eclipse.swt.widgets.Display.windowProc(Display.java:4408)
    at org.eclipse.swt.internal.gtk.OS._gtk_main_do_event(Native Method)
    at org.eclipse.swt.internal.gtk.OS.gtk_main_do_event(OS.java:8422)
    at org.eclipse.swt.widgets.Display.eventProc(Display.java:1245)
    at org.eclipse.swt.internal.gtk.OS._g_main_context_iteration(Native Method)
    at org.eclipse.swt.internal.gtk.OS.g_main_context_iteration(OS.java:2276)
    at org.eclipse.swt.widgets.Display.readAndDispatch(Display.java:3207)
    at org.eclipse.ui.internal.Workbench.runEventLoop(Workbench.java:2701)
    at org.eclipse.ui.internal.Workbench.runUI(Workbench.java:2665)
    at org.eclipse.ui.internal.Workbench.access$4(Workbench.java:2499)
    at org.eclipse.ui.internal.Workbench$7.run(Workbench.java:679)
    at org.eclipse.core.databinding.observable.Realm.runWithDefault(Realm.java:332)
    at org.eclipse.ui.internal.Workbench.createAndRunWorkbench(Workbench.java:668)
    at org.eclipse.ui.PlatformUI.createAndRunWorkbench(PlatformUI.java:149)
    at org.eclipse.ui.internal.ide.application.IDEApplication.start(IDEApplication.java:123)
    at org.eclipse.equinox.internal.app.EclipseAppHandle.run(EclipseAppHandle.java:196)
    at org.eclipse.core.runtime.internal.adaptor.EclipseAppLauncher.runApplication(EclipseAppLauncher.java:110)
    at org.eclipse.core.runtime.internal.adaptor.EclipseAppLauncher.start(EclipseAppLauncher.java:79)
    at org.eclipse.core.runtime.adaptor.EclipseStarter.run(EclipseStarter.java:344)
    at org.eclipse.core.runtime.adaptor.EclipseStarter.run(EclipseStarter.java:179)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:601)
    at org.eclipse.equinox.launcher.Main.invokeFramework(Main.java:622)
    at org.eclipse.equinox.launcher.Main.basicRun(Main.java:577)
    at org.eclipse.equinox.launcher.Main.run(Main.java:1410)

   Locked ownable synchronizers:
    - None

"VM Thread" prio=3 tid=0x08209c00 nid=0x2 runnable 

"VM Periodic Task Thread" prio=3 tid=0x0825d000 nid=0x8 waiting on condition 

JNI global references: 713
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1 回答 1

1

您的系统时钟是否有可能在跳动？

Eclipse 的事件循环用于System.currentTimeMillis()跟踪时间，并且currentTimeMillis不能保证是单调的（不像System.nanoTime()本来那样。）

long timeout = System.currentTimeMillis() + 500;
while (System.currentTimeMillis() < timeout) {
    eventPtr = OS.gdk_event_get ();
    if (eventPtr != 0) {
        break;
    } else {
        try {Thread.sleep(50);} catch (Exception ex) {}
    }
}

如果是这样，作为您在“ Is there a way to interrupt a sleep thread in a running JVM, without access to the application's code? ”中请求的解决方法，您可以轻松地使用 JBoss Byteman 创建一个规则集，该规则集从一定数量的睡眠后的睡眠循环。

Foo.java：

public class Foo {

    public void test1() {
        long timeout = System.currentTimeMillis() + 500;
        int i = 0;
        while (System.currentTimeMillis() < timeout) {
            System.out.println(i++);
            try {Thread.sleep(50);} catch (Exception ex) {}
        }
    }


    public static void main(final String ... args) throws Exception {
        new Foo().test1();
    }

}

卧铺.btm:

RULE counter
CLASS Foo
METHOD test1
AT ENTRY
IF TRUE
DO createCountDown($0, 5)
ENDRULE

RULE sleeper
CLASS Foo
METHOD test1
AT INVOKE Thread.sleep()
IF countDown($0)
DO RETURN
ENDRULE

使用 Byteman 脚本运行：

$ ~/Downloads/byteman-download-2.1.0/bin/bmjava.sh -l ./sleeper.btm Foo
0
1
2
3
4
5

正常运行：

$ java Foo 
0
1
2
3
4
5
6
7
8
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于 2012-09-01T07:48:45.330 回答