是否有任何 SQL 脚本可以将度/分/秒(保存在 A 列中)转换为小数(保存在新的 B 列中)?我搜索了现有的解决方案,但所有示例均指小数->度/分/秒。我很欣赏任何例子,因为我不擅长 SQL 脚本。
问问题
12188 次
4 回答
4
以下似乎有效:
SELECT DMS, DEGREES + (MINUTES / 60) + (SECONDS / (60 * 60)) AS DECIMAL_DEGREES
FROM (SELECT DMS,
TRUNC(DMS) AS DEGREES,
TRUNC((DMS - TRUNC(DMS)) * 100) AS MINUTES,
((DMS * 100) - TRUNC(DMS * 100)) * 100 AS SECONDS
FROM TEST_DMS)
或者,如果您更喜欢将其全部作为一种表达方式:
SELECT DMS,
TRUNC(DMS) +
(TRUNC((DMS - TRUNC(DMS)) * 100) / 60) +
(((DMS * 100) - TRUNC(DMS * 100)) * 100) / (60 * 60) AS DECIMAL_DEGREES
FROM TEST_DMS
至少这些与我可信赖的、生锈的 HP-41C 返回的结果一致。:-)
分享和享受。
于 2012-08-30T11:32:16.103 回答
1
我从事一个项目...我使用脚本来解决 oracle db 上的 DMS 转换问题
SELECT
CASE
WHEN LENGTH(longitude)=7 THEN ROUND (cast(substr(longitude, 1, 1) as numeric(10,5)) + cast(substr(longitude, 3, 2) as numeric(10,5))/60 + cast(substr(longitude, 6, 2) as numeric(10,5))/3600,4)
WHEN LENGTH(longitude)=8 THEN ROUND (cast(substr(longitude, 1, 2) as numeric(10,5)) + cast(substr(longitude, 4, 2) as numeric(10,5))/60 + cast(substr(longitude, 7, 2) as numeric(10,5))/3600,4)
ELSE
ROUND (CAST (longitude as Numeric(10,5)),4)
END AS LONGITUDE,
CASE
WHEN LENGTH(latitude)=7 THEN ROUND (cast(substr(latitude, 1, 1) as numeric(10,5)) + cast(substr(latitude, 3, 2) as numeric(10,5))/60 + cast(substr(latitude, 6, 2) as numeric(10,5))/3600,4)
WHEN LENGTH(latitude)=8 THEN ROUND (cast(substr(latitude, 1, 2) as numeric(10,5)) + cast(substr(latitude, 4, 2) as numeric(10,5))/60 + cast(substr(latitude, 7, 2) as numeric(10,5))/3600,4)
ELSE
ROUND (CAST (latitude as Numeric(10,5)),4)
END AS LATITUDE
于 2013-07-26T08:46:56.547 回答
0
我用下面的做同样的事情
declare @cord varchar (max)
set @cord= '2504N 05534E'
select
case when CHARINDEX(' ', @cord,1)>0 then
case when right(LTrIM(RTRIM(left( @cord, CHARINDEX(' ', @cord,1)-1))),1) = 'N' then
(left(LTrIM(RTRIM(left( @cord, CHARINDEX(' ', @cord,1)-1))),2))
+
(SUBSTRING(LTrIM(RTRIM(left( @cord, CHARINDEX(' ', @cord,1)-1))),3,2)/60.0)
else
-1*(
(left(LTrIM(RTRIM(left( @cord, CHARINDEX(' ', @cord,1)-1))),2))
+
(SUBSTRING(LTrIM(RTRIM(left( @cord, CHARINDEX(' ', @cord,1)-1))),3,2)/60.0)
)
end
end latitude
,case when CHARINDEX(' ', @cord,1)>0 then
case when right(LTrIM(RTRIM(SUBSTRING( @cord, CHARINDEX(' ', @cord,1),100))),1) = 'E' then
(left(LTrIM(RTRIM(SUBSTRING( @cord, CHARINDEX(' ', @cord,1),100))),3) )
+
(SUBSTRING( LTrIM(RTRIM(SUBSTRING( @cord, CHARINDEX(' ', @cord,1),100))),4
,2)/60.0)
else
-1*(
(left(LTrIM(RTRIM(SUBSTRING( @cord, CHARINDEX(' ', @cord,1),100))),3) )
+
(SUBSTRING( LTrIM(RTRIM(SUBSTRING( @cord, CHARINDEX(' ', @cord,1),100))),4
,2)/60.0)
)
end
end longitude
,geography::Point(
case when CHARINDEX(' ', @cord,1)>0 then
case when right(LTrIM(RTRIM(left( @cord, CHARINDEX(' ',
@cord,1)-1))),1) = 'N' then
(left(LTrIM(RTRIM(left( @cord, CHARINDEX(' ', @cord,1)-1))),2))
+
(SUBSTRING(LTrIM(RTRIM(left( @cord, CHARINDEX(' ',
@cord,1)-1))),3,2)/60.0)
else
-1*(
(left(LTrIM(RTRIM(left( @cord, CHARINDEX(' ', @cord,1)-1))),2))
+
(SUBSTRING(LTrIM(RTRIM(left( @cord, CHARINDEX(' ',
@cord,1)-1))),3,2)/60.0)
)
end
end
,case when CHARINDEX(' ', @cord,1)>0 then
case when right(LTrIM(RTRIM(SUBSTRING( @cord, CHARINDEX(' ',
@cord,1),100))),1) = 'E' then
(left(LTrIM(RTRIM(SUBSTRING( @cord, CHARINDEX(' ',
@cord,1),100))),3) )
+
(SUBSTRING( LTrIM(RTRIM(SUBSTRING( @cord, CHARINDEX(' ',
@cord,1),100))),4 ,2)/60.0)
else
-1*(
(left(LTrIM(RTRIM(SUBSTRING( @cord, CHARINDEX(' ',
@cord,1),100))),3) )
+
(SUBSTRING( LTrIM(RTRIM(SUBSTRING( @cord, CHARINDEX(' ',
@cord,1),100))),4 ,2)/60.0)
)
end
end
, 4326)
as geography_Point
于 2018-10-19T08:10:31.443 回答
0
基于@user2621989 的回答,这里测试了他的查询的 SQL Server 版本:
DECLARE @longitude varchar(max) = '50°03''10"'
DECLARE @latitude varchar(max) = '15°00''50"'
SELECT
CASE
WHEN LEN(@longitude)=8 THEN ROUND (cast(SUBSTRING(@longitude, 1, 1) as numeric(9,6)) + cast(SUBSTRING(@longitude, 3, 2) as numeric(9,6))/60 + cast(SUBSTRING(@longitude, 6, 2) as numeric(9,6))/3600,4)
WHEN LEN(@longitude)=9 THEN ROUND (cast(SUBSTRING(@longitude, 1, 2) as numeric(9,6)) + cast(SUBSTRING(@longitude, 4, 2) as numeric(9,6))/60 + cast(SUBSTRING(@longitude, 7, 2) as numeric(9,6))/3600,4)
ELSE
ROUND (CAST (@longitude as numeric(9,6)),4)
END AS longitude,
CASE
WHEN LEN(@latitude)=8 THEN ROUND (cast(SUBSTRING(@latitude, 1, 1) as numeric(9,6)) + cast(SUBSTRING(@latitude, 3, 2) as numeric(9,6))/60 + cast(SUBSTRING(@latitude, 6, 2) as numeric(9,6))/3600,4)
WHEN LEN(@latitude)=9 THEN ROUND (cast(SUBSTRING(@latitude, 1, 2) as numeric(9,6)) + cast(SUBSTRING(@latitude, 4, 2) as numeric(9,6))/60 + cast(SUBSTRING(@latitude, 7, 2) as numeric(9,6))/3600,4)
ELSE
ROUND (CAST (@latitude as numeric(9,6)),4)
END AS latitude
退货
longitude latitude
50.05280000000 15.01390000000
于 2019-11-22T08:55:04.467 回答