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通过查询,我得到了这个字符串"Order::Resource(PPP32#BB300320LQ00J#AAAR05504)"。我想在 # 字符之前、之间和之后提取字符串,如下所示:

ID = PPP32

sub_id = BB300320LQ00J

sup_id =AAAR05504

有谁知道如何做到这一点?

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2 回答 2

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declare @start int, @end int, @secondstring varchar(100)

select @start = charindex('#',@string)
select @secondstring = substring(@string, @start+1, len(@string))

select @end = charindex('#',@secondstring)

select substring(@string,1, @start-1),
       substring(@string,@start+1,@end-1), 
       substring(@string, @start+@end+1, len(@string)-@end)
于 2012-08-29T09:21:41.253 回答
3

这是正确的解决方案:

declare @string varchar(50)
select @string = 'Order::Resource(PPP32#BB300320LQ00J#AAAR05504)'
declare @start int, @end int, @secondstring varchar(100)

select @start = charindex('#',@string)
select @secondstring = substring(@string, @start+1, len(@string))

select @end = charindex('#',@secondstring)

select substring(@string,charindex('(', @string)+1, @start-1-charindex('(', @string)),
       substring(@string,@start+1,@end-1), 
       substring(@string, @start+@end+1, len(@string)-(@start+@end+1))
于 2012-08-29T09:32:13.533 回答