2

我在我的项目中使用spring mvc3,我对请求映射模式(url中的最后一个斜杠)感到困惑

以下面的控制器方法为例:

@RequestMapping(value = "/{id}/edit", method = RequestMethod.GET)
public String edit(@PathVariable int id, Model model) {
    model.addAttribute(postDao.query(id));
    return "posts/edit";
}

获取url“ http://localhsot/app/posts/3/edit”时有效,但获取url“”时无法使用该方法http://localhsot/app/posts/3/edit/

我知道我可以像这样设置请求映射值:

@RequestMapping(value = {"/{id}/edit","/{id}/edit/"})

但我想知道是否有其他解决方案?Rails 似乎会忽略 url 中的最后一个斜杠。

更新:

servlet-context.xml:

<mvc:annotation-driven />
<mvc:view-controller path="/" view-name="home" />
<context:component-scan base-package="com.king.controller" />
<mvc:resources mapping="/res/**" location="/res/" />
<bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
    <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" />
    <property name="prefix" value="/WEB-INF/jsp/" />
    <property name="suffix" value=".jsp" />
</bean>

web.xml

<filter>
    <filter-name>httpMethodFilter</filter-name>
    <filter-class>org.springframework.web.filter.HiddenHttpMethodFilter</filter-class>
</filter>

<filter-mapping>
    <filter-name>httpMethodFilter</filter-name>
    <servlet-name>modelServlet</servlet-name>
</filter-mapping>
<servlet>
    <servlet-name>modelServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>modelServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>
4

1 回答 1

4

我认为您正在尝试解决错误的问题。

如果你匹配一个带有和不带斜杠的 URL,你会因为重复的内容而从搜索引擎中得到一个糟糕的评级。

我要做的是添加一个过滤器,它使用状态码发送所有请求而不使用斜杠重定向带有斜杠(反之亦然)HttpServletResponse.SC_MOVED_PERMANENTLY

这是这种过滤器的最小实现:

public class CanonicalUrlFilter implements Filter {
    @Override
    public void init(final FilterConfig filterConfig) throws ServletException { }

    @Override
    public void doFilter(final ServletRequest servletRequest, final ServletResponse servletResponse,
            final FilterChain filterChain) throws IOException, ServletException {
        if (servletRequest instanceof HttpServletRequest) {
            HttpServletRequest hsr = (HttpServletRequest) servletRequest;
            if (hsr.getMethod().equals("GET") && !hsr.getRequestURI().endsWith("/") && (hsr.getQueryString() == null)) {
                HttpServletResponse response = (HttpServletResponse) servletResponse;
                response.setStatus(HttpServletResponse.SC_MOVED_PERMANENTLY);
                response.sendRedirect(hsr.getRequestURI() + "/");
                return;
            }
        }

        filterChain.doFilter(servletRequest, servletResponse);
    }

    @Override
    public void destroy() { }
}
于 2012-08-29T09:02:47.243 回答