sql - 在两列的值之间选择记录

Question

我有下表，它保存了一年中特定周的销售数据。

销售量

week | year | value
50   | 2011 | 150
51   | 2011 | 151
52   | 2011 | 152
1    | 2012 | 170
2    | 2012 | 190
3    | 2012 | 180
4    | 2012 | 160
5    | 2012 | 170
6    | 2012 | 290

我想查找位于第 1 年第 1 周和第 2 年第 2 周之间的记录。

例如

1. 2011 年第 50 周至 2012 年第 5 周之间
2. 2012 年第 1 周至 2012 年第 6 周之间

由于在 SQL 方面的经验很少，我尝试了以下查询，该查询适用于案例 2，但不适用于案例 1。

SELECT * from sales WHERE (week >= 1 AND year >= 2012) AND (week <= 6 AND year <= 2012 ) 

据我了解，条件分组似乎不起作用。就好像没有条件分组一样。

Answer 1

select *
from
(
   Select *, year*100 + week as yearweek
   from table
) v
where yearweek between 201150 and 201205

Answer 2

通过比较临时记录更简单、更快、更优雅：

SELECT *
FROM   tbl
WHERE (year, week) BETWEEN (2011, 50) AND (2012, 5);

这个密切相关的答案有更多详细信息，包括基准测试和一些更多可能的解决方案。

Answer 3

此查询适用于案例 1：

SELECT * from sales WHERE (week >= 50 AND year = 2011) OR (week <= 5 AND year = 2012 )

而这应该适用于大多数相邻年份的情况（例如 2011 年和 2012 年或其他，但不是 2001 年至 2010 年）。这种情况有点复杂，但仍然相当简单。

DECLARE @week1 INT
DECLARE @week2 INT
DECLARE @year1 INT
DECLARE @year2 INT

SELECT * from sales WHERE (week >= @week1 AND year = @year1) OR (week <= @week2 AND year = @year2 )

好的，这是更大范围的示例。

DECLARE @week1 INT
DECLARE @week2 INT
DECLARE @year1 INT
DECLARE @year2 INT

SELECT * from sales WHERE (week >= @week1 AND year = @year1) OR (week <= @week2 AND year = @year2 ) OR (year > @year1 AND year < @year2)
-- This last one gives ALL weeks for the full years between year1 and year2 (e.g. all weeks for 2002-2009 if we choose dates between 2001 and 2010)

Answer 4

试试这个作为第一个例子

    SELECT * 
    FROM sales 
    WHERE (year = 2011 AND week > 50) 
       OR (year = 2012 AND week < 5)

一般来说

    SELECT * 
    FROM sales 
    WHERE (year = 'year1' AND week > 'week1') 
       OR  (year > 'year1' AND year < 'year2' ) 
       OR (year = 'year2' AND week < 'week2' )