1

在下面的 HTML 中,我可以解析table元素,但我不知道如何跳过th元素。

我只想获取td元素,但是当我尝试使用时:

foreach (HtmlNode cell in row.SelectNodes("td"))

...我有一个例外。

<table class="tab03">
  <tbody>
    <tr>
      <th class="right" rowspan="2">first</th>
    </tr>
    <tr>
      <th class="right">lp</th>
      <th class="right">name</th>
    </tr>
    <tr>
      <td class="right">1</td>
      <td class="left">house</td>
    </tr>
    <tr>
      <th class="right" rowspan="2">Second</th>
    </tr>
    <tr>
      <td class="right">2</td>
      <td class="left">door</td>
    </tr>
  </tbody>
</table>

我的代码:

var document = doc.DocumentNode.SelectNodes("//table");
string store = "";

if (document != null)
{
    foreach (HtmlNode table in document)
    {
        if (table != null)
        {
            foreach (HtmlNode row in table.SelectNodes("tr"))
            {
                store = "";
                foreach (HtmlNode cell in row.SelectNodes("th|td"))
                {
                    store = store + cell.InnerText+"|";
                }

                sw.Write(store );
                sw.WriteLine();  
            }
        }
    }
}

sw.Flush();
sw.Close(); 
4

2 回答 2

3

您的 XPath 语法不正确。请试试:

HtmlNode cell in row.SelectNodes("//td")

这将为您提供td可以迭代的元素集合foreach

于 2012-08-28T22:21:22.683 回答
3

此方法使用 LINQ 查询HtmlNode具有 name 的实例td

我还注意到您的输出显示为val|val|(带有尾管),此示例string.Join(pipe, array)用作删除该尾管的不那么可怕的方法:val|val

using System.Linq;

// ...

var tablecollection = doc.DocumentNode.SelectNodes("//table");
string store = string.Empty;

if (tablecollection != null)
{
    foreach (HtmlNode table in tablecollection)
    {
        // For all rows with at least one child with the 'td' tag.
        foreach (HtmlNode row in table.DescendantNodes()
            .Where(desc =>
                desc.Name.Equals("tr", StringComparison.OrdinalIgnoreCase) &&
                desc.DescendantNodes().Any(child => child.Name.Equals("td",
                    StringComparison.OrdinalIgnoreCase))))
        {
            // Combine the child 'td' elements into an array, join with the pipe
            // to create the output in 'val|val|val' format.
            store = string.Join("|", row.DescendantNodes().Where(desc =>
                desc.Name.Equals("td", StringComparison.OrdinalIgnoreCase))
                .Select(desc => desc.InnerText));

            // You can probably get rid of the 'store' variable as it's
            // no longer necessary to store the value of the table's
            // cells over the iteration.
            sw.Write(store);
            sw.WriteLine();
        }
    }
}

sw.Flush();
sw.Close(); 
于 2012-08-28T23:23:19.853 回答