2

我正在尝试对同一张表上以下三个查询的结果求和以生成一份报告。

SELECT b.BG_SEVERITY as Severity, count (b.BG_BUG_ID) as Total
FROM BUG b where
 b.BG_USER_12='QA3'
 group by b.BG_SEVERITY

SELECT s.BG_SEVERITY as Severity, count (s.BG_BUG_ID) as Total
FROM BUG s where
 s.BG_USER_12='QA1'
 group by s.BG_SEVERITY

SELECT a.BG_SEVERITY as Severity, count (a.BG_BUG_ID) as Total
FROM BUG a where
 a.BG_USER_12='QA2'
 group by a.BG_SEVERITY

每个查询的结果如下所示：

Severity   Total
1-Critical  4
2-High      94
3-Medium    23
4-Low       45

我正在寻找合并/总结上述三个查询中的“总计”列。我可以使用 SQL 的哪些功能来执行此操作？

4

2 回答 2

2

如果使用 sql-server，您可以尝试使用 union。像这样的东西：

SELECT
    Severity,
    SUM(Total)
FROM
    (
    SELECT b.BG_SEVERITY as Severity, count (b.BG_BUG_ID) as Total FROM BUG b where b.BG_USER_12='QA3' group by b.BG_SEVERITY
    UNION ALL
    SELECT s.BG_SEVERITY as Severity, count (s.BG_BUG_ID) as Total FROM BUG s where s.BG_USER_12='QA1' group by s.BG_SEVERITY    
    UNION ALL 
    SELECT a.BG_SEVERITY as Severity, count (a.BG_BUG_ID) as Total FROM BUG a where a.BG_USER_12='QA2' group by a.BG_SEVERITY
    ) tbl
GROUP BY
    Severity
于 2012-08-28T05:48:20.583 回答
2

你可以IN在你的条件下使用。

SELECT   b.BG_SEVERITY as Severity, 
         COUNT(b.BG_BUG_ID) as Total
FROM     BUG b 
WHERE    b.BG_USER_12 IN ('QA3','QA1','QA2')
GROUP BY b.BG_SEVERITY
于 2012-08-28T05:48:54.687 回答