我需要在查询结果中添加一个额外的列,
该列需要称为百分比,如果col1 == 0
则应percent
包含NIS
elsepercent
应包含ceil(col2 / col1 * 100)
所以我相信以下应该有效:
IF(col1 = 0, 'NIS', ceil(col2 / col1 * 100)) as percent
但是我遇到了一个问题,因为 col1 和 col2 也是复合的。
COUNT(distinct i.id) as col1
COUNT(distinct q.id) as col2
所以我受到打击
“字段列表”中的未知列“col1”
我可以解决这个问题
IF(COUNT(distinct i.id) = 0, 'NIS', ceil(COUNT(distinct q.id) / COUNT(distinct i.id) * 100)) as percent
但这对我来说似乎是一堆额外的处理,肯定有更好的方法吗?
完整查询
SELECT
`t`.*,
`r`.`name` AS region_name,
GROUP_CONCAT(DISTINCT p.ptype_id SEPARATOR "|") AS ptype_ids,
COUNT(DISTINCT q.id) AS quoted,
COUNT(DISTINCT i.id) AS intended,
COUNT(DISTINCT qa.id) AS awarded,
IF(
intended = 0,
`"NIS"`,
CEIL(quoted / intended * 100)
) AS percent
FROM
(`tradesmen` t)
LEFT JOIN `regions` r
ON `r`.`id` = `t`.`region_id`
LEFT JOIN `quotes` q
ON `t`.`id` = `q`.`tradesman_id`
LEFT JOIN `quote_intentions` i
ON `t`.`id` = `i`.`tradesman_id`
LEFT JOIN `quotes` qa
ON `q`.`tradesman_id` = `qa`.`tradesman_id`
AND qa.accepted = 1
LEFT JOIN `ptypes_tradesmen` p
ON `p`.`tradesman_id` = `t`.`id`
GROUP BY `t`.`id`
LIMIT 20