3

我正在制作一个双重链接列表。该错误与我的 Remove 方法有关。我想不通。有人知道吗?

这是哪里的错误?

错误 1 ​​错误 C2027:使用未定义类型 'DoublyListNode' c:\users\conor\documents\college\c++\projects\repeat - doublylinkedlist\repeat - doublylinkedlist\doublylinkedlist.h 230 1 重复 - DoublyLinkedList

// -------------------------------------------------------------------------------------------------------
//  Name:           Remove
//  Description:    Removes the node that the iterator points to, moves iterator forward to the next node.
//  Arguments:      p_iterator: The iterator to remove
//                  isForward: Tells which direction the iterator was going through the list
//  Return Value:   None.
// -------------------------------------------------------------------------------------------------------
void Remove(DoublyListIterator<Datatype>& m_itr)
{
    DoublyListNode<Datatype>* node = m_head;
    // if the iteratordoesn’t belong to this list, do nothing.
    if (m_itr.m_list != this)
        return;
    // if node is invalid, do nothing.
    if (m_itr.m_node == 0)
        return;
    if (m_itr.m_node == m_head)
    {
        // move the iteratorforward and delete the head.
        m_itr.Forth();
        RemoveHead();
        m_size--;
    }
    else
    {
        // scan forward through the list until you find
        // the node prior to the node you want to remove
        while (node->m_next != m_itr.m_node)
            node = node->m_next;
        // move the iterator forward.
        m_itr.Forth();
        // if the node you are deleting is the tail,
        // update the tail node.
        if (node->m_next == m_tail)
        {
            m_tail = node;
        }
        // delete the node.
        delete node->m_next;
        // re-link the list.
        node->m_next = m_itr.m_node;
        m_size--;
    }
}

如果需要更多代码,请询问。我不想在 Stack 溢出用户身上放很多代码。

4

2 回答 2

4

The problem was a typo of the class DoublyListNode. The class was names DLNode. So this gave the error being discussed above.

于 2012-08-25T20:39:27.603 回答
3

您正在检查尾节点,但不检查头和尾之间的节点。甚至在将节点链接到下一个成员之前,您就通过删除节点来破坏链。

让我们分析一下:-

while (node->m_next != m_itr.m_node)
            node = node->m_next;

在循环node->m_next点之后m_itr.m_node

    delete node->m_next;
    // re-link the list.
    node->m_next = m_itr.m_node;

您正在分配一个已删除的节点!!!!

更改代码:-

node->m_next = m_itr.m_node;
delete m_itr;
于 2012-08-25T19:39:00.023 回答