13

昨天运行良好，没有更改代码。

echo date("M", strtotime("-3 month", time()) );
echo date("M", strtotime("-2 month", time()) );
echo date("M", strtotime("-1 month", time()) );
echo date("M", time());

它昨天产生的输出与您预期的一样 - 即四月，五月，六月，七月

今天它呼应五月五月七月七月

有任何想法吗？

提前致谢。

4

6 回答 6

15

它可能与错误#44073有关

你可以尝试这样的事情：

echo date("M", strtotime("-3 month", strtotime(date("F") . "1")) ) . "\n";
echo date("M", strtotime("-2 month", strtotime(date("F") . "1")) ) . "\n";
echo date("M", strtotime("-1 month", strtotime(date("F") . "1")) ) . "\n";
echo date("M", time()) . "\n";

（在评论部分找到的解决方案strtotime；直接链接）

和输出：

Apr
May
Jun
Jul

日期格式和月份名称的“作弊”等等......

于 2009-07-31T10:38:22.690 回答
10

Gorden correctly identified the issue, but I wanted to give another solution that was helpful and not as technical. Just use "first day of" or "last day of" in your strtotime. Ex, these following examples overcome the issue on a 31st of a month:

// Today is May 31st
//All the following return 2012-04-30
echo date('Y-m-d', strtotime("last day of -1 month"));
echo date('Y-m-d', strtotime("last day of last month"));
echo date_create("last day of -1 month")->format('Y-m-d'); 

// All the following return 2012-04-01
echo date('Y-m-d', strtotime("first day of -1 month")); 
echo date('Y-m-d', strtotime("first day of last month"));
echo date_create("first day of -1 month")->format('Y-m-d');
于 2012-05-31T16:24:37.850 回答
5

试试这个而不是strtotime：

mktime(0, (date("n") - 3 + 12) % 12, 1)

想法是获取当前月份数 ( date("n"))，从中减去所需的月份数（此处-3），将 12 添加到它，然后得到模 12。

于 2009-07-31T10:40:42.407 回答
4

This is known and expected behavior. The reason for this is that a month is a relative date with no fixed length. From http://www.gnu.org/software/tar/manual/html_node/Relative-items-in-date-strings.html#SEC120

The unit of time displacement may be selected by the string ‘year’ or ‘month’ for moving by whole years or months. These are fuzzy units, as years and months are not all of equal duration. More precise units are ‘fortnight’ which is worth 14 days, ‘week’ worth 7 days, ‘day’ worth 24 hours, ‘hour’ worth 60 minutes, ‘minute’ or ‘min’ worth 60 seconds, and ‘second’ or ‘sec’ worth one second. An ‘s’ suffix on these units is accepted and ignored.

Consequently (emphasis mine)

The fuzz in units can cause problems with relative items. For example, ‘2003-07-31 -1 month’ might evaluate to 2003-07-01, because 2003-06-31 is an invalid date. To determine the previous month more reliably, you can ask for the month before the 15th of the current month. For example:

$ date -R
Thu, 31 Jul 2003 13:02:39 -0700
$ date --date='-1 month' +'Last month was %B?'
Last month was July?
$ date --date="$(date +%Y-%m-15) -1 month" +'Last month was %B!'
Last month was June!

The above could be expressed in PHP as

echo date('M', strtotime(date('Y-m-') . '15 -1 month'));

Also see the commments below http://bugs.php.net/bug.php?id=22486

于 2011-05-31T06:10:50.547 回答
2

From PHP 5.3 (Ref: https://bugs.php.net/bug.php?id=44073) and higher you can do:

"first day of +1 month" or "first day of next month" or even "last day of next month"

Example:

$date = '2015-12-31';

echo date("Y-m-d", strtotime($date ."first day of previous month"));

Will produce: 2015-11-01 This does not calculate days on +30 days time basis.

于 2016-03-05T12:52:07.793 回答
0

a simple way could be to write it like this

echo date("M", strtotime("this year +3 months"));

or

echo date("M", strtotime("this month -3 months"));

depends what your using it for..

于 2012-03-18T16:28:22.747 回答