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我有3个表结构...

歌曲(id,状态)

曲目列表(id、song_id、artist_id、状态)

艺术家(身份,身份)

我希望有 HABTM,所以我提到了.. Song MODEL

var $hasAndBelongsToMany = array(
    'Artist' => array(
        'className' => 'Artist',
        'joinTable' => 'tracklists',
        'foreignKey' => 'song_id',
        'associationForeignKey' => 'artist_id',
        'conditions' => array('tracklist.status' => '1')
    'with' => 'Tracklist',
    //'unique' => true
    ),
);

艺术家模特

 var $hasAndBelongsToMany = array(
    'Song' => array(
        'className' => 'Song',
        'joinTable' => 'tracklists',
        'foreignKey' => 'artist_id',
        'associationForeignKey' => 'song_id',
        'with' => 'Tracklist',
        //'unique' => true
    ),
);

曲目列表模型 var $belongsTo = array(

    'Song' => array(
        'className' => 'Song',
        'foreignKey' => 'song_id',
        'dependent' => true
    ),
    'Artist' => array(
        'className' => 'Artist',
        'foreignKey' => 'artist_id',
        'dependent' => true
    )
);

这种方式但问题是当我试图从 Artist 表中查找记录时,它会毫无条件地找到所有记录。

    $artist_conditions = array('Artist.status' => '1');
    $artist_list = $this->Song->Artist->find('list', array('conditions' => $artist_conditions ));

我希望只获取与 tracklist 相关且 tracklist.status 为的艺术家1。关系对吗??或者我只是将 hasMany 与(歌曲,艺术家)一起使用,将 BelongsTo 与(曲目列表)一起使用。

4

1 回答 1

0

你可以试试这个:

/* for example in songs controller */
    public $uses = array('Song','Tracklist');
    $artist_conditions = array('Artist.status' => '1');
    $this->Tracklist->recursive = 1;
    $artist_list = $this->Tracklist->find('list', array('conditions' => $artist_conditions ));
于 2012-08-24T20:49:58.287 回答