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我有以下Recipe类，它正在实现Parcelable类。但是当我将对象从一个类传递到另一个类时，它的属性值为null. 为什么？

配方类：

package mobile.bh.classes;

import java.util.ArrayList;

import mobile.bh.activities.MethodStep;
import android.graphics.Bitmap;
import android.os.Parcel;
import android.os.Parcelable;

//simple class that just has one member property as an example
public class Recipe implements Parcelable {
    public int id;
    public String name;
    public ArrayList<Ingredient> ingredients;
    public ArrayList<MethodStep> method;
    public String comment;
    public String image;
    public Bitmap image2;

    public Recipe(){}
    /* everything below here is for implementing Parcelable */

    // 99.9% of the time you can just ignore this
    public int describeContents() {
        return 0;
    }

    // write your object's data to the passed-in Parcel
    public void writeToParcel(Parcel out, int flags) {
        out.writeInt(id);
        out.writeString(name);
        out.writeList(ingredients);
        out.writeList(method);
        out.writeString(comment);
        out.writeString(image);
    }

    // this is used to regenerate your object. All Parcelables must have a CREATOR that implements these two methods
    public static final Parcelable.Creator<Recipe> CREATOR = new Parcelable.Creator<Recipe>() {
        public Recipe createFromParcel(Parcel in) {
            return new Recipe(in);
        }

        public Recipe[] newArray(int size) {
            return new Recipe[size];
        }
    };

    // example constructor that takes a Parcel and gives you an object populated with it's values
    private Recipe(Parcel in) {
        in.writeInt(id);
        in.writeString(name);
        in.writeList(ingredients);
        in.writeList(method);
        in.writeString(comment);
        in.writeString(image);
        }
}

虽然发送对象intent

    Intent i = new Intent(context,RecipeInfoActivity.class);
    i.putExtra("recipeObj", recipe);

在另一边接收物体

Recipe p = (Recipe) getIntent().getParcelableExtra("recipeObj");

但p.name值为null

4

3 回答 3

1

在 Parcelable 构造函数中，您需要从包裹中回读。

private Recipe(Parcel in) {
        id = in.readInt();
        name =in.readString();
        ingredients = in.readList();
        method = in.readList();
        comment = in.readString();
        }
于 2012-08-24T14:49:14.833 回答
0

您应该在构造函数中使用 readInt 而不是 writeInt （其他字段等）

于 2012-08-24T14:48:56.907 回答
0

首先，在您的构造函数中，您似乎试图将所有属性写入包裹，但据我所知，它们尚未设置；可能你打算从那里的包裹中阅读？现在我不确定这个 Parcel 到底是什么，但我在想它是某种类似于 Properties 的类？如果是这样，Java 就不是按引用传递的。这意味着只是修改传递给您的方法的值不会修改真实 Parcel 的值，您必须返回修改后的 Parcel

于 2012-08-24T14:49:23.160 回答