c# - 从字符串中删除列及其值

Question

我有三个字符串

string a = "[ERROR] = any thing And [ID] > 20 And [NAME] like Varun";
string b = "[AGE] < 60 Or [ERROR] like Exception And [ID] > 20 And [NAME] like Varun And [ERROR] = any thing ";
string c = "[ID] > 20 And`enter code here` [NAME] like Varun And [ERROR] = any thing";

我想删除从 [ERROR] 开始的字符串到下一个运算符，如 And/Or.....

我想要像这样的答案

string a = "[ID] > 20 And [NAME] like Varun";
string b = "[AGE] < 60 And [ID] > 20 And [NAME] like Varun";
string c = "[ID] > 20 And [NAME] like Varun";

我怎样才能删除..???

Answer 1

如果您对正则表达式不满意（我假设您不满意），您可以使用以下伪代码：

1. 将字符串拆分为单词（以空格分隔）

2. 扫描单词列表，如果相等[ERROR]则跳过所有单词直到下一个单词开头[和结尾]

3. 如果单词以开头[和结尾，]则将其添加到输出以及所有后续不以 a 开头和以 a[结尾的单词]。

   public static String FilterString(string value)
   {
     string[] lsWords = value.Split(' ');
     StringBuilder lsbBuilder = new StringBuilder();
   
     bool lbIncluding = true;
   
     foreach(String lsWord in lsWords)
     {
       if (lsWord.StartsWith("[") && lsWord.EndsWith("]"))
          lbIncluding = (lsWord != "[ERROR]");
   
       if (lbIncluding)
       {
         if (lsbBuilder.Length > 0) lsbBuilder.Append(' ');
         lsbBuilder.Append(lsWord);
       }
     }
   
     return lsbBuilder.ToString();
   }
   

   ……

   string a = "[ERROR] = any thing And [ID] > 20 And [NAME] like Varun";
   string b = "[AGE] < 60 Or [ERROR] like Exception And [ID] > 20 And [NAME] like Varun And [ERROR] = any thing ";
   string c = "[ID] > 20 And`enter code here` [NAME] like Varun And [ERROR] = any thing";
   
   a = FilterString(a);
   b = FilterString(b);
   c = FilterString(c);
   

这是输出：

[ID] > 20 And [NAME] like Varun
[AGE] < 60 Or [ID] > 20 And [NAME] like Varun And
[ID] > 20 And`enter code here` [NAME] like Varun And

这并没有摆脱 ANDS / ORS 等，你需要自己做一个，但这应该给你一个很好的起点。