1

我有一个NSArray自定义对象，它们都有一个 @propertyname类型NSString。如何快速枚举数组并创建一个新数组，该数组仅包含name属性中具有特定单词的对象？

例如：

CustomObject *firstObject = [[CustomObject alloc] init];
firstObject.name = @"dog";

CustomObject *secondObject = [[CustomObject alloc] init];
secondObject.name = @"cat";

CustomObject *thirdObject = [[CustomObject alloc] init];
thirdObject.name = @"dogs are fun";

NSMutableArray *testArray = [NSMutableArray arrayWithObjects:firstObject,
                                                             secondObject,
                                                             thirdObject, 
                                                             nil];

// I want to create a new array that contains all objects that have the word 
// "dog" in their name property.

我知道我可以像这样使用 for 循环：

NSMutableArray *newArray = [NSMutableArray array];
for (CustomObject *obj in testArray)
{
    if ([obj.name rangeOfString:@"dog"].location == NSNotFound) {
        //string wasn't found
    }

    else {
        [newArray addObject:obj];
    }
}

但是有没有更有效的方法？谢谢！

4

2 回答 2

5 
NSString *searchString = @"dog";
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF.name contains %@", searchString];
NSArray *filteredArray = [testArray filteredArrayUsingPredicate:predicate];
于 2012-08-23T21:01:56.107 回答
1

请看一下NSPredicates！当您搜索/过滤数组结果时，它们非常高效。这是文档！

于 2012-08-23T20:59:59.193 回答