复制构造函数用于许多事情,例如当我需要使用指针或为对象动态分配内存时。但是看这个例子tutorialpoint.com
:
#include <iostream>
using namespace std;
class Line
{
public:
int getLength( void );
Line( int len ); // simple constructor
Line( const Line &obj); // copy constructor
~Line(); // destructor
private:
int *ptr;
};
// Member functions definitions including constructor
Line::Line(int len)
{
cout << "Normal constructor allocating ptr" << endl;
// allocate memory for the pointer;
ptr = new int;
*ptr = len;
}
Line::Line(const Line &obj)
{
cout << "Copy constructor allocating ptr." << endl;
ptr = new int;
*ptr = *obj.ptr; // copy the value
}
Line::~Line(void)
{
cout << "Freeing memory!" << endl;
delete ptr;
}
int Line::getLength( void )
{
return *ptr;
}
void display(Line obj)
{
cout << "Length of line : " << obj.getLength() <<endl;
}
// Main function for the program
int main( )
{
Line line(10);
display(line);
return 0;
}
结果是:
Normal constructor allocating ptr
Copy constructor allocating ptr.
Length of line : 10
Freeing memory!
Freeing memory!
当我注释掉(复制构造函数)和析构函数中的代码时,我得到了相同的结果:
Normal constructor allocating ptr
Length of line : 10
那么在这里使用复制构造函数有什么区别呢?还有为什么“释放内存!” 发生两次?