我已经制作了 android 应用程序，其中使用 php 从数据库（MYSQL）中获取图像。我也得到了图像，但问题是我想将图像传递给另一个活动，即从 gridview 到 viewflipper 以便滑动图像。
请任何人都可以帮助我如何传递从数据库中获取的点击图像。
提前致谢。
显示活动.java
公共类 DisplayImages 扩展 Activity{
ImageView imageview;
JSONObject json1= JSONfunction.getJSONfromURL("http://www.zxxxxcssxxxxxx.com/app/photo.php");
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_display_images);
JSONArray catgry = null;
try {
catgry = json1.getJSONArray("photo");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
final GridView gridView=(GridView)findViewById(R.id.gridview);
ImageAdapter adapter=new ImageAdapter(this,catgry);
gridView.setAdapter(adapter);
/**
* On Click event for Single Gridview Item
* */
gridView.setOnItemClickListener(new OnItemClickListener(){
public void onItemClick(AdapterView<?> parent, View view, int position,
long id) {
// TODO Auto-generated method stub
Image img=new Image();
Object imagename=view.getTag();
if(position==0)
img.setImageBitmap(getImageBitmap("http://www.aaa.com/thumb_photo_3.jpg"));
if(position==1)
img.setImageBitmap(getImageBitmap("http://www.aaa.com/thumb_photo_4.jpg"));
if(position==2)
img.setImageBitmap(getImageBitmap("http:/www.aaa.com/thumb_photo_5.jpg"));
if(position==3)
img.setImageBitmap(getImageBitmap("http://www.aaa.com/thumb_photo_6.jpg"));
if(position==4)
img.setImageBitmap(getImageBitmap("http://www.aaa.com/thumb_photo_7.jpg"));
if(position==5)
img.setImageBitmap(getImageBitmap("http://www.aaa.com/thumb_photo_8.jpg"));
if(position==6)
img.setImageBitmap(getImageBitmap("http://www.aaa.com/thumb_photo_9.jpg"));
if(position==7)
img.setImageBitmap(getImageBitmap("http://www.aaa.com/thumb_photo_10.jpg"));
if(position==8)
img.setImageBitmap(getImageBitmap("http://www.aaa.com/thumb_photo_11.jpg"));
if(position==9)
img.setImageBitmap(getImageBitmap("http://www.aaa.com/thumb_photo_12.jpg"));
if(position==10)
img.setImageBitmap(getImageBitmap("http://www.aaa.com/thumb_photo_13.jpg"));
Toast.makeText(DisplayImages.this, "" + imagename,
Toast.LENGTH_SHORT).show();
Intent intent=new Intent(getApplicationContext(),FullSizeImageActivity.class);
//Create Parcelable object
ParcelableImage parcelableImage=new ParcelableImage(img);
//store Parcelable Object in intent
intent.putExtra("img", parcelableImage);
startActivity(intent);
}
});
}
private Bitmap getImageBitmap(String url) {
Bitmap bm = null;
try {
URL aURL = new URL(url);
URLConnection conn = aURL.openConnection();
conn.connect();
InputStream is = conn.getInputStream();
BufferedInputStream bis = new BufferedInputStream(is);
bm = BitmapFactory.decodeStream(bis);
bis.close();
is.close();
} catch (IOException e) {
//Log.e(TAG, "Error getting bitmap", e);
}
return bm;
}
}
我正在传递gridview中该位置的图像路径onclick。但我想获取图像的图像路径onclick。我如何动态获取图像路径并传递另一个活动。
这是我的图像适配器的代码
公共类 ImageAdapter 扩展 BaseAdapter {
public ImageView[] mImages;
String qrimage;
static class ViewHolder{
ImageView image;
}
JSONObject json1= JSONfunction.getJSONfromURL("http://www.zzzzzxxxxxxxxxx.com/app/photo.php");
private Context context;
public ImageAdapter(Context mcontext,JSONArray imageArrayJson) {
// TODO Auto-generated constructor stub
this.context=mcontext;
this.mImages = new ImageView[imageArrayJson.length()];
for(int i=0;i<imageArrayJson.length();i++){
JSONObject image;
try {
ImageView imageView;
imageView = new ImageView(context);
imageView.setScaleType(ImageView.ScaleType.CENTER_CROP);
imageView.setLayoutParams(new GridView.LayoutParams(90, 90));
image = imageArrayJson.getJSONObject(i);
qrimage="http://www.aaa.com/"+image.getString("thumbsize");
//imageView.setImageBitmap(getImageBitmap(qrimage));
mImages[i]= new ImageView(context);
mImages[i].setImageBitmap(getImageBitmap(qrimage));
mImages[i].setTag("Image"+i);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}