我刚刚将我的 mysql 代码重写为 PDO,但我只是没有让它工作。我一直在调试,但似乎并不正确。这对我来说是全新的,但它连接到数据库,它从我的 vardump 中的数据库中读取,但它不会在 textarea 中发布,甚至不会回显。更不用说写入数据库了……我有一种直觉,就是 $result var 在做一些奇怪的事情,但据我所知,我仔细检查了所有内容。
<html>
<head>
<title>Milan CMS</title>
</head>
<body>
<?php
$host= "";
$dbname= "";
$username= "";
$password= "";
$dbh = new PDO("mysql:host=$host;dbname=$dbname", $username, $password);
$sth = $dbh->prepare("SELECT * FROM milan WHERE tag='trainingen'");
$sth->execute();
$result = $sth->fetchAll();
var_dump($result);
echo $result['value'];
echo $result;
?>
<form action="<?php echo $_SERVER['PHP_SELF'];?>" method="post" name="trainingen">
Trainingen:<textarea name="nametrainingen" rows="10" cols="60"><?php echo $result['value']; ?></textarea></p>
<input name="submit" type="submit" value="Verzenden"><input type="reset" value="Veld leeg maken">
</form>
<?php
$invoer = $_POST['nametrainingen'];
if (isset($_POST['submit'])) { //test if submit button is clicked
$sql = "DELETE FROM milan WHERE tag = 'trainingen'";
$sql = "INSERT INTO milan (tag, value) VALUES ('trainingen', '$result')";
$sth->execute();
$result = $sth->fetchAll();
$myFile = "trainingen.json";
$fh = fopen($myFile, 'w') or die("can't open file");
fwrite($fh, json_encode($result));
fclose($fh);}
?>
<p>
</body>
</html>
var_dump 的输出:
array(1) {
[0]=> array(6) {
["id"]=> string(1) "0"
[0]=> string(1) "0"
["tag"]=> string(10) "trainingen"
[1]=> string(10) "trainingen"
["value"]=> string(17) "Hgioejigojerigjer"
[2]=> string(17) "Hgioejigojerigjer"
}
}