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我搜索了答案，但没有找到答案，所以它让我在 stackowerflow 注册。我正在尝试使用 win32 ole 编写简单的 perl 脚本，它将遍历所有 M$ 单词段落（任何以硬返回结尾的文本）并仅打印与指定条件匹配的那些段落。问题是我需要访问字体大小属性。在我看来，这个属性在第一段中只设置了一次，之后没有更新。请看以下代码：

#!/usr/bin/perl
use strict;
use warnings;
use Win32::OLE::Const 'Microsoft Word';
#$Win32::OLE::CP = CP_UTF8;
binmode STDOUT, 'encoding(utf8)';

# OPEN FILE SPECIFIED AS FIRST ARGUMENT
my $fname=$ARGV[0];
my $fnameFullPath = `cygpath.exe -wa $fname`;
$fnameFullPath =~ s/\\/\\\\/g;
$fnameFullPath =~ s/\s*$//;
unless (-e $fnameFullPath) { print "Error: File did not exists\n"; exit 1;}

# STARTING OLE
my $Word = Win32::OLE->GetActiveObject('Word.Application')
    || Win32::OLE->new('Word.Application','Quit')
    or die Win32::OLE->LastError();

$Word->{'Visible'} = 0;
my $doc = $Word->Documents->Open($fnameFullPath);
my $paragraphs = $doc->Paragraphs() ;
my $enumerate = new Win32::OLE::Enum($paragraphs);

# PROCESSING PARAGRAPHS
while(defined(my $paragraph = $enumerate->Next())) {

    my $text = $paragraph->{Range}->{Text};
    my $sel = $Word->Selection;
    my $font = $sel->Font;

    if ($font->{Size} == 18){
        print "Text: ", $text, "\n";
        print "Font Bold: ", $font->{Bold}, "\n";
        print "Font Italic: ", $font->{Italic}, "\n";
        print "Font Name: ", $font->{Name}, "\n";
        print "Font Size: ", $font->{Size}, "\n";
        print "=========\n";
    }
}

# CLOSING OLE
$Word->ActiveDocument->Close ;
$Word->Quit;

这是我得到的输出：

Text: This is a doc file containing different fonts and size, document also contain header and footer (Font: TNR, Size: 18)
Font Bold: 0
Font Italic: 0
Font Name: Times New Roman
Font Size: 18
=========
Text: This is a Perl example (Font TNR, Size: 12)
Font Bold: 0
Font Italic: 0
Font Name: Times New Roman
Font Size: 18
=========
Text: This is a Python example(Font: Courier New, Size: 10)
Font Bold: 0
Font Italic: 0
Font Name: Times New Roman
Font Size: 18
=========

正如您在输出中看到的那样，字体大小为 18，即使原始文档中的大小不同（字体名称也未更新）。这让我假设 $font 在处理的第一段中只设置一次。因此以下条件

if ($font->{Size} == 18)

仅在第一个处理的段落中进行评估。这也支持以下事实：如果我将条件更改为以下（匹配第 2 段）：

if ($font->{Size} == 12)

输出什么都没有。因为第一段是 18 而不是 12，因此条件为假，$font 不再更新，所以它永远不会为真。我做错了什么？

非常感谢

4

1 回答 1

1

查看#Insert this code代码段中的它现在可以正常工作。 

# PROCESSING PARAGRAPHS

while(defined(my $paragraph = $enumerate->Next())) {

    #Insert this code
    $paragraph->{Range}->Select(); 
    sleep(1);
    #-------------

    my $text = $paragraph->{Range}->{Text};    
    my $sel = $Word->Selection;
    my $font = $sel->Font;

    if ($font->{Size} == 18){
        print "Text: ", $text, "\n";
        print "Font Bold: ", $font->{Bold}, "\n";
        print "Font Italic: ", $font->{Italic}, "\n";
        print "Font Name: ", $font->{Name}, "\n";
        print "Font Size: ", $font->{Size}, "\n";
        print "=========\n";
    }
}
于 2014-01-08T06:00:32.050 回答