mysql - 没有连接条件的两个表的结果

Question

我有这样的查询

SELECT COUNT(u.user_id) AS count1 FROM users WHERE user_id>1001 
UNION
SELECT COUNT(c.hits) AS count2 FROM source c WHERE loginid LIKE 'fb%';

结果

count1 
250
56

像这样单行怎么做

count1   count2
250      56

Answer 1

您可以使用子查询来实现此目的：

select 
      (SELECT COUNT(u.user_id) AS count1 from users where user_id>1001) as count1,
      (select count(c.hits) AS count2 from source  c where loginid like 'fb%') as count2

Answer 2

SELECT SUM(count1) AS count1,
       SUM(count2) AS count2
FROM(
    SELECT COUNT(u.user_id) AS count1, 0 AS count2 from users where user_id>1001

    UNION ALL

    SELECT 0 AS count1, count(c.hits) AS count2 from source  c where loginid like 'fb%';
)a;