2

我正在使用 ksoap2 在 Android 中调用 java webservice。Java Web 服务方法是,

ImageProcessImpl.java

public UserResponse sample(UserRequest userRequest) {
     return ImageProcessDAO.sample(userRequest);
}

ImageProcessDAO.java

public static String sample(UserRequest userRequest) {
     System.out.println(userRequest.getClientName());
     UserResponse UserResponse = new UserResponse();
     userResponse.setMessage("SUCCESS");
     return userResponse;
}

我将这些来自 Android 的网络服务称为:

try{
        String NAMESPACE = "http://impl.test.com";
        String URL = "http://10.0.2.2:8080/Webservice/services/ImageProcessImpl?wsdl";  
        String SOAP_ACTION = "http://impl.test.com/sample";
        String METHOD_NAME = "sample";

        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); 

        UserRequest userRequest = new UserRequest();            
        userRequest.setClientName("Test");

        PropertyInfo pi = new PropertyInfo();
        pi.setName("userRequest");
        pi.setValue(userRequest);
        pi.setType(UserRequest.class);
        request.addProperty(pi);

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
        envelope.setOutputSoapObject(request);  
        envelope.implicitTypes = true;
        envelope.addMapping(NAMESPACE, "UserResponse", UserResponse.class);

        AndroidHttpTransport httpTransport = new AndroidHttpTransport(URL);  
        httpTransport.debug = true;
        httpTransport.call(SOAP_ACTION, envelope);

       UserResponse response = (UserResponse) envelope.getResponse(); 
       Log.e(Test.LOG_TAG, response.getMessage());
        }catch (Exception e) {
            Log.e(Test.LOG_TAG, "throws an exception: " + e.getMessage());
        }

但是我的 Logcat 中的错误是“引发异常:无法序列化:com.test.common.UserRequest ”。如何修复此错误?这是调用复杂类型的 Web 服务的正确方法吗?

我的 wsdl 文件是,

<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions targetNamespace="http://impl.test.com" xmlns:apachesoap="http://xml.apache.org/xml-soap" xmlns:impl="http://impl.test.com" xmlns:intf="http://impl.test.com" xmlns:tns1="http://common.test.com" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:wsdlsoap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<!--WSDL created by Apache Axis version: 1.4
Built on Apr 22, 2006 (06:55:48 PDT)-->
 <wsdl:types>
  <schema elementFormDefault="qualified" targetNamespace="http://impl.test.com" xmlns="http://www.w3.org/2001/XMLSchema">
   <import namespace="http://common.test.com"/>
   <element name="sample">
    <complexType>
     <sequence>
      <element name="userRequest" type="tns1:UserRequest"/>
     </sequence>
    </complexType>
   </element>
   <element name="sampleResponse">
    <complexType>
     <sequence>
      <element name="sampleReturn" type="tns1:UserResponse"/>
     </sequence>
    </complexType>
   </element>
  </schema>
  <schema elementFormDefault="qualified" targetNamespace="http://common.test.com" xmlns="http://www.w3.org/2001/XMLSchema">
   <complexType name="UserRequest">
    <sequence>
     <element name="clientName" nillable="true" type="xsd:string"/>
    </sequence>
   </complexType>
   <complexType name="UserResponse">
    <sequence>
     <element name="message" nillable="true" type="xsd:string"/>
    </sequence>
   </complexType>
  </schema>
 </wsdl:types>

   <wsdl:message name="sampleRequest">

      <wsdl:part element="impl:sample" name="parameters">

      </wsdl:part>

   </wsdl:message>

   <wsdl:message name="sampleResponse">

      <wsdl:part element="impl:sampleResponse" name="parameters">

      </wsdl:part>

   </wsdl:message>

   <wsdl:portType name="ImageProcessImpl">

      <wsdl:operation name="sample">

         <wsdl:input message="impl:sampleRequest" name="sampleRequest">

       </wsdl:input>

         <wsdl:output message="impl:sampleResponse" name="sampleResponse">

       </wsdl:output>

      </wsdl:operation>

   </wsdl:portType>

   <wsdl:binding name="ImageProcessImplSoapBinding" type="impl:ImageProcessImpl">

      <wsdlsoap:binding style="document" transport="http://schemas.xmlsoap.org/soap/http"/>
      <wsdl:operation name="sample">

         <wsdlsoap:operation soapAction=""/>

         <wsdl:input name="sampleRequest">

            <wsdlsoap:body use="literal"/>

         </wsdl:input>

         <wsdl:output name="sampleResponse">

            <wsdlsoap:body use="literal"/>

         </wsdl:output>

      </wsdl:operation>

   </wsdl:binding>

   <wsdl:service name="ImageProcessImplService">

      <wsdl:port binding="impl:ImageProcessImplSoapBinding" name="ImageProcessImpl">

         <wsdlsoap:address location="http://localhost:8080/Webservice/services/ImageProcessImpl"/>

      </wsdl:port>

   </wsdl:service>

</wsdl:definitions>

我使用了 KvmSerializable。我 private Client[] clientNameList = null;在 UserRequest.java 中又添加了一个数组 bean 变量。

当我调用 Web 服务时,它在请求中工作正常。但在响应中,我得到一个包含所有值的字符串。响应字符串如下所示。

anyType{clientNameList=anyType{clientNameList=anyType{clientID=1; }; clientNameList=anyType{clientID=2; }; }; message=SUCCESS; }.

我怎样才能解析这个字符串?

用户响应.java

public class UserResponse implements KvmSerializable{

public String message = null;
public Client[] clientNameList = null;

@Override
public Object getProperty(int index) {
    switch (index){
    case 0:
        return message;
    case 1:
        return clientNameList;
     default:
         return null;
    }
}

@Override
public int getPropertyCount() {
    // TODO Auto-generated method stub
    return 2;
}

@Override
public void getPropertyInfo(int index, Hashtable arg1, PropertyInfo info) {
    switch(index)
    {
    case 0:
        info.type = PropertyInfo.STRING_CLASS;
        info.name = "message";
        break;
    case 1:
        info.type = PropertyInfo.OBJECT_TYPE;
        info.name = "clientNameList";
        break;
    default:
        break;
    }

}

@Override
public void setProperty(int index, Object value) {
    switch(index)
    {
    case 0:
        message = value.toString();
        break;
    case 1:
        clientNameList = (Client[]) value;
        break;
    default:
        break;
    }

}   
}

Client.java 仅包含 Integer 类型的 clientId。

更新了代码和 wsdl

ImageProcessImpl.java

public UserResponse sample(UserRequest userRequest) {
     return ImageProcessDAO.sample(userRequest);
}

ImageProcessDAO.java

public static String sample(UserRequest userRequest) {
    System.out.println(userRequest.getClientName());
    UserResponse userResponse = new UserResponse();
    userResponse.setMessage(SUCCESS);
    Client[] clients = new Client[2];
    Client client = null;
    for(int i=0;i<2;i++)
    {
        client = new Client();
        client.setClientID(i+1);
        clients[i] = client;
    }
    userResponse.setClientNameList(clients);
    return userResponse;
}

我将这些来自 Android 的网络服务称为:

try{
        String NAMESPACE = "http://impl.test.com";
        String URL = "http://10.0.2.2:8080/Webservice/services/ImageProcessImpl?wsdl";  
        String SOAP_ACTION = "http://impl.test.com/sample";
        String METHOD_NAME = "sample";

        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); 

        UserRequest userRequest = new UserRequest();            
        userRequest.setClientName("Test");

        PropertyInfo pi = new PropertyInfo();
        pi.setName("userRequest");
        pi.setValue(userRequest);
        pi.setType(UserRequest.class);
        request.addProperty(pi);

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
        envelope.setOutputSoapObject(request);  
        envelope.implicitTypes = true;
        envelope.addMapping(NAMESPACE, "userRequest", UserRequest.class);
        envelope.addMapping(NAMESPACE, "UserResponse", UserResponse.class);

        AndroidHttpTransport httpTransport = new AndroidHttpTransport(URL);  
        httpTransport.debug = true;
        httpTransport.call(SOAP_ACTION, envelope);

       SoapObject result = (SoapObject) envelope.getResponse();
       userResponse.message = result.getProperty(0).toString();
       Log.e(Test.LOG_TAG, userResponse.message);
        }catch (Exception e) {
            Log.e(Test.LOG_TAG, "throws an exception: " + e.getMessage());
        }

我的新 wsdl 文件是,

<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions targetNamespace="http://impl.test.com" xmlns:apachesoap="http://xml.apache.org/xml-soap" xmlns:impl="http://impl.test.com" xmlns:intf="http://impl.test.com" xmlns:tns1="http://common.test.com" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:wsdlsoap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<!--WSDL created by Apache Axis version: 1.4
Built on Apr 22, 2006 (06:55:48 PDT)-->
 <wsdl:types>
  <schema elementFormDefault="qualified" targetNamespace="http://impl.test.com" xmlns="http://www.w3.org/2001/XMLSchema">
   <import namespace="http://common.test.com"/>
   <element name="sample">
    <complexType>
     <sequence>
      <element name="userRequest" type="tns1:UserRequest"/>
     </sequence>
    </complexType>
   </element>
   <element name="sampleResponse">
    <complexType>
     <sequence>
      <element name="sampleReturn" type="tns1:UserResponse"/>
     </sequence>
    </complexType>
   </element>
   <complexType name="ArrayOf_tns1_Client">
    <sequence>
     <element maxOccurs="unbounded" minOccurs="0" name="item" type="tns1:Client"/>
    </sequence>
   </complexType>
  </schema>
  <schema elementFormDefault="qualified" targetNamespace="http://common.test.com" xmlns="http://www.w3.org/2001/XMLSchema">
   <import namespace="http://impl.test.com"/>
   <complexType name="UserRequest">
    <sequence>
     <element name="clientName" nillable="true" type="xsd:string"/>
    </sequence>
   </complexType>
   <complexType name="Client">
    <sequence>
     <element name="clientID" type="xsd:int"/>
    </sequence>
   </complexType>
   <complexType name="UserResponse">
    <sequence>
     <element name="clientNameList" nillable="true" type="impl:ArrayOf_tns1_Client"/>
     <element name="message" nillable="true" type="xsd:string"/>
    </sequence>
   </complexType>
  </schema>
 </wsdl:types>

   <wsdl:message name="sampleRequest">

      <wsdl:part element="impl:sample" name="parameters">

      </wsdl:part>

   </wsdl:message>

   <wsdl:message name="sampleResponse">

      <wsdl:part element="impl:sampleResponse" name="parameters">

      </wsdl:part>

   </wsdl:message>

   <wsdl:portType name="ImageProcessImpl">

      <wsdl:operation name="sample">

         <wsdl:input message="impl:sampleRequest" name="sampleRequest">

       </wsdl:input>

         <wsdl:output message="impl:sampleResponse" name="sampleResponse">

       </wsdl:output>

      </wsdl:operation>

   </wsdl:portType>

   <wsdl:binding name="ImageProcessImplSoapBinding" type="impl:ImageProcessImpl">

      <wsdlsoap:binding style="document" transport="http://schemas.xmlsoap.org/soap/http"/>

      <wsdl:operation name="sample">

         <wsdlsoap:operation soapAction=""/>

         <wsdl:input name="sampleRequest">

            <wsdlsoap:body use="literal"/>

         </wsdl:input>

         <wsdl:output name="sampleResponse">

            <wsdlsoap:body use="literal"/>

         </wsdl:output>

      </wsdl:operation>

   </wsdl:binding>

   <wsdl:service name="ImageProcessImplService">

      <wsdl:port binding="impl:ImageProcessImplSoapBinding" name="ImageProcessImpl">

         <wsdlsoap:address location="http://localhost:8080/Webservice/services/ImageProcessImpl"/>

      </wsdl:port>

   </wsdl:service>

</wsdl:definitions>
4

2 回答 2

5

我会坚持简单地获取 XML 中的响应并使用任何 XML Parser 来解析更容易的响应。另外我会坚持你使用ksoap2-android-assembly-2.5.4-jar-with-dependencies.jar你正在使用的那个已被弃用。

AndroidHttpTransport 正在被取代HttpTransportSE

以下是如何在 XML 中获得响应,

HttpTransportSE androidHttpTransport = new HttpTransportSE(URL, 100);
androidHttpTransport.debug=true; 
androidHttpTransport.call(SOAP_ACTION, envelope);
String response = androidHttpTransport.responseDump;
Log.d("Response in XML", response);

您将在 String 中获得响应,response并且您可以使用SAX或任何其他 XML 解析器对其进行解析。

于 2012-08-23T04:32:51.553 回答
2

您的 UserRequest 类需要实现 org.ksoap2.serialization.KvmSerializable。

于 2012-08-22T12:57:32.450 回答