javascript - 基于时间的不均匀计数计时器Jquery

Question

我一直在寻找一个基于一天中时间的 jquery 计数计时器，但我很难找到一个，所以在这里我只写了我自己的。这是给任何正在寻找的人。

目标是获取一天中的时间，计算当前时间当天的百分比，将其乘以目标总和并开始添加以创建现实的时间场景。我的计时器正在触发以创建不稳定数据流的模拟，但您可以轻松地将其更改为稳定增加。

带数字的元素是#counter，物镜总和是3.5mm。

Answer 1

var currentNumber;

$(document).ready(function (e) {
    var currDate = new Date();
    var mins = currDate.getMinutes();
    var hours = currDate.getHours();
    var seconds = currDate.getSeconds();
    var combined = (hours * 60 * 60) + (mins * 60) + seconds;
    var percentage = (combined / 90000);
    var startingPoint = Math.round(3500000 * percentage);
    currentNumber = startingPoint;

    $('#counter').html(formatNumber(startingPoint));

    setTimeout(function () {
        updateNumber(currentNumber)
    }, 100);
});

function updateNumber(startingPoint) {
    if (startingPoint % 58 === 0) {
        startingPoint += 5;
        currentNumber = startingPoint;
        $('#counter').html(formatNumber(currentNumber));
        setTimeout(function () {
            updateNumber(currentNumber)
        }, 850);
    } else if (startingPoint % 22 === 0) {
        startingPoint += 4;
        currentNumber = startingPoint;
        $('#counter').html(formatNumber(currentNumber));
        setTimeout(function () {
            updateNumber(currentNumber)
        }, 500);
    } else if (startingPoint % 6 === 0) {
        startingPoint += 1;
        currentNumber = startingPoint;
        $('#counter').html(formatNumber(currentNumber));
        setTimeout(function () {
            updateNumber(currentNumber)
        }, 75); 
    } else {        
        startingPoint += 5;
        currentNumber = startingPoint;
        $('#counter').html(formatNumber(currentNumber));
        setTimeout(function () {
            updateNumber(currentNumber)
        }, 250);
    }
}

function formatNumber(number) {
    return addCommas((number).toFixed(0));
}

function addCommas(nStr) {
    nStr += '';
    x = nStr.split('.');
    x1 = x[0];
    x2 = x.length > 1 ? '.' + x[1] : '';
    var rgx = /(\d+)(\d{3})/;
    while (rgx.test(x1)) {
        x1 = x1.replace(rgx, '$1' + ',' + '$2');
    }
    return x1 + x2;
}