13

我有一个用于我的表单的 GUI 线程和另一个计算事物的线程。

该表单有一个richtTextBox。我希望工作线程将字符串传递给表单,以便每个字符串都显示在文本框中。

每次在工作线程中生成一个新字符串时,我都会调用一个事件,现在应该显示该字符串。但我不知道如何传递字符串!这是我到目前为止所尝试的:

///// Form1
private void btn_myClass_Click(object sender, EventArgs e)
{
    myClass myObj = new myClass();
    myObj.NewListEntry += myObj_NewListEntry;
    Thread thrmyClass = new Thread(new ThreadStart(myObj.ThreadMethod));
    thrmyClass.Start();
}

private void myObj_NewListEntry(Object objSender, EventArgs e)
{
    this.BeginInvoke((MethodInvoker)delegate
    {
        // Here I want to add my string from the worker-thread to the textbox!
        richTextBox1.Text += "TEXT"; // I want: richTextBox1.Text += myStringFromWorkerThread;
    });
}

///// myClass (working thread...)
class myClass
{
    public event EventHandler NewListEntry;

    public void ThreadMethod()
    {
        DoSomething();
    }

    protected virtual void OnNewListEntry(EventArgs e)
    {
        EventHandler newListEntry = NewListEntry;
        if (newListEntry != null)
        {
            newListEntry(this, e);
        }
    }

    private void DoSomething()
    {
        ///// Do some things and generate strings, such as "test"...
        string test = "test";


        // Here I want to pass the "test"-string! But how to do that??
        OnNewListEntry(EventArgs.Empty); // I want: OnNewListEntry(test);
    }
}
4

4 回答 4

24

像这样

public class NewListEntryEventArgs : EventArgs
{
    private readonly string test;

    public NewListEntryEventArgs(string test)
    {
        this.test = test;
    }

    public string Test
    {
        get { return this.test; }
    }
}

然后你像这样声明你的类

class MyClass
{
    public delegate void NewListEntryEventHandler(
        object sender,
        NewListEntryEventArgs args);

    public event NewListEntryEventHandler NewListEntry;

    protected virtual void OnNewListEntry(string test)
    {
        if (NewListEntry != null)
        {
            NewListEntry(this, new NewListEntryEventArgs(test));
        }
    }
}

并在订阅中Form

private void btn_myClass_Click(object sender, EventArgs e)
{
    MyClass myClass = new MyClass();
    myClass.NewListEntry += NewListEntryEventHandler;
    ...
}

private void NewListEntryEventHandler(
    object sender,
    NewListEntryEventArgs e)
{
    if (richTextBox1.InvokeRequired)
    {
        this.Invoke((MethodInvoker)delegate
            {             
                this.NewListEntryEventHandler(sender, e);
            });
        return;
    }

    richTextBox1.Text += e.Test;
}

我冒昧地使NewListEntryEventArgs类不可变,因为这是有道理的。我还部分更正了您的命名约定,在方便的地方进行了简化和更正。

于 2012-08-21T13:20:07.760 回答
4

您需要通过继承 EventArgs 创建一个新类。

于 2012-08-21T13:02:58.777 回答
3

创建您自己的EventArgs.

像这样做:

public class MyEventArgs : EventArgs
{
   public string MyEventString {get; set; }

   public MyEventArgs(string myString)
   {
       this.MyEventString = myString;
   }
}

然后在您的代码中替换为EventArgsMyEventArgs创建一个MyEventArgs包含您的字符串的对象。

然后您可以使用MyEventArgs实例访问它.MyEventString

所以你会做这样的事情:

///// myClass (working thread...)
class myClass
{
    public event EventHandler NewListEntry;

    public void ThreadMethod()
    {
        DoSomething();
    }

    protected virtual void OnNewListEntry(MyEventArgs e)
    {
        EventHandler newListEntry = NewListEntry;
        if (newListEntry != null)
        {
            newListEntry(this, e);
        }
    }

    private void DoSomething()
    {
        ///// Do some things and generate strings, such as "test"...
        string test = "test";

        OnNewListEntry(new MyEventArgs(test));
    }
}

并以您的形式:

private void myObj_NewListEntry(Object objSender, MyEventArgs e)
{
    this.BeginInvoke((MethodInvoker)delegate
    {
        // Here I want to add my string from the worker-thread to the textbox!
        richTextBox1.Text += e.MyEventString;
    });
}
于 2012-08-21T13:07:26.010 回答
1

一般来说,您需要继承EventArgs并添加一个string属性,然后将您的事件设为 类型EventHandler<YourEventArgs>,但这是BackgroundWorker.

示例:http: //msdn.microsoft.com/en-us/library/cc221403 (v=vs.95).aspx

在这里: C# backgroundWorker 报告字符串?

于 2012-08-21T13:05:46.413 回答