1

有4张桌子:

  • 补充,字段:( Code_name,Code_name_arch,Tasknum,Pki_num,Group_eng,Name,Descr,Cost,Quan,shop);

  • 制造商,字段:(Code_maker,Code_maker_arch,Code_name,提供者);

  • 到达,字段:(Code_arr,Code_maker,quan_arr);

  • 帐户、字段:(Code_acc、Code_maker、num_acc、quan_acc、summ)

我的查询是:

ALTER Procedure [dbo].[pr_tblz] As
Set NOCOUNT ON
Declare @task VARCHAR(4000)
Select @task = coalesce(@task + ',[' + [Tasknum] + ']',
'[' + [Tasknum] + ']')
FROM [db_pki].[dbo].[Suppl]
Group BY [Tasknum]
Order BY [Tasknum]
Declare @query VARCHAR(8000)
Set @query='
Alter View Amountzz As
SELECT Shop, Name, Desc, Group_eng as GI, '+ @task +', quan_arr As specif, quan_acc As acns 
FROM 
(
select
Shop, Name, Desc, Group_eng, Tasknum, Quan, quan_arr, quan_acc
from [db_pki].[dbo].[Suppl] as deliveries
LEFT JOIN [db_pki].[dbo].[Maker] ON (deliveries.[Code_name] = [db_pki].[dbo].[Maker].[Code_name])
LEFT JOIN [db_pki].[dbo].[Arrival] ON ([db_pki].[dbo].[Maker].[Code_maker] = [db_pki].[dbo].[Arrival].[Code_maker])
LEFT JOIN [db_pki].[dbo].[Accounts] ON ([db_pki].[dbo].[Maker].[Code_maker] = [db_pki].[dbo].[Accounts].[Code_maker])
)date_to_pivot
PIVOT 
(
Max([Quan])
For [Tasknum]
IN (' + @task + ')
 )AS p'
Execute (@query)

结果:

Shop      Name     Descr    GI    n1     n2      n3 ...    specif    acns
1         name1      1       5    4                           1        1
2 10      name2      2       3    8                           2        2
3         name3      3       501         11                   3        3
1 8       name1      1       5           16                   7        10
a 2 10    name2      2       3                   3            5        6
5         name1      1       2                   5            6        3

我怎样才能得到以下结果?

Shop      Name     Descr    GI    n1     n2      n3 ...    specif    acns
1 8       name1      1       5    4      16                 8(1+7)     11
a 2 10    name2      2       3    8              3            7        8(2+6)
3         name3      3      501          11                   3        3
5         name1      1       2                   5            6        3

n1,n2,n3,... - 任务编号

4

1 回答 1

0

未测试。尝试聚合 ,和的值Shop,在旋转之前拉出列的子选择,如下所示(必要的更改以粗体突出显示):specifacns

ALTER Procedure [dbo].[pr_tblz] As
Set NOCOUNT ON
Declare @task VARCHAR(4000)
Select @task = coalesce(@task + ',[' + [Tasknum] + ']',
'[' + [Tasknum] + ']')
FROM [db_pki].[dbo].[Suppl]
Group BY [Tasknum]
Order BY [Tasknum]
Declare @query VARCHAR(8000)
Set @query='
Alter View Amountzz As
SELECT Shop, Name, Desc, Group_eng as GI, '+ @task +', quan_arr As specif, quan_acc As acns 
FROM 
(
select
MAX(Shop    ) OVER (PARTITION BY Name) AS Shop,
Name, Desc, Group_eng, Tasknum, Quan,
SUM(quan_arr) OVER (PARTITION BY Name) AS quan_arr,
SUM(quan_acc) OVER (PARTITION BY Name) AS quan_acc
from [db_pki].[dbo].[Suppl] as deliveries
LEFT JOIN [db_pki].[dbo].[Maker] ON (deliveries.[Code_name] = [db_pki].[dbo].[Maker].[Code_name])
LEFT JOIN [db_pki].[dbo].[Arrival] ON ([db_pki].[dbo].[Maker].[Code_maker] = [db_pki].[dbo].[Arrival].[Code_maker])
LEFT JOIN [db_pki].[dbo].[Accounts] ON ([db_pki].[dbo].[Maker].[Code_maker] = [db_pki].[dbo].[Accounts].[Code_maker])
)date_to_pivot
PIVOT 
(
Max([Quan])
For [Tasknum]
IN (' + @task + ')
 )AS p'
Execute (@query)
于 2012-08-22T13:58:59.327 回答