我有一个数据库,其中包括三个表,如下所示:
-播放器
-球员以前的俱乐部
-以前的俱乐部
“球员以前的俱乐部”表是一个查找表,因为球员和以前的俱乐部之间存在多对多的关系。
现在我有下面的代码,它成功地从一个表单中填充了“玩家”表和“以前的俱乐部表”。
if (isset($_GET['addform']))
{
include $_SERVER['DOCUMENT_ROOT'] . '/includes/db.inc.php';
//PLAYER TABLE INSERT
try
{
$sql = 'INSERT INTO player SET
name = :name,
age = :age,
position = :position,
height = :height,
weight = :weight,
satscore = :satscore,
gpa = :gpa';
$s = $pdo->prepare($sql);
$s->bindValue(':name', $_POST['name']);
$s->bindValue(':age', $_POST['age']);
$s->bindValue(':position', $_POST['position']);
$s->bindValue(':height', $_POST['height']);
$s->bindValue(':weight', $_POST['weight']);
$s->bindValue(':satscore', $_POST['satscore']);
$s->bindValue(':gpa', $_POST['gpa']);
$s->execute();
}
catch (PDOException $e)
{
$error = 'Error adding submitted player profile.' . $e->getMessage();
include 'error.html.php';
exit();
}
//PREVIOUS CLUBS TABLE INSERT
try
{
$sql = 'INSERT INTO previousclubs SET
name = :previousclubs';
$s = $pdo->prepare($sql);
$s->bindValue(':previousclubs', $_POST['previousclubs']);
$s->execute();
}
catch (PDOException $e)
{
$error = 'Error adding previous club.' . $e->getMessage();
include 'error.html.php';
exit();
}
header('Location: .');
exit();
}
我不确定如何填充查找表(球员以前的俱乐部),因为它需要的值不是通过表单传递的,它们是通过自动增量功能生成的。
该表由两个字段组成。一个是 player 表的主键值,另一个是之前的 clubs 表的主键值。
这两个字段一起形成一个联合主键。
非常感谢有关如何执行此操作的任何帮助。
谢谢
更新
好的,我现在有以下代码:
if (isset($_GET['addform']))
{
include $_SERVER['DOCUMENT_ROOT'] . '/includes/db.inc.php';
//PLAYER TABLE INSERT
try
{
$sql = 'INSERT INTO player SET
name = :name,
age = :age,
position = :position,
height = :height,
weight = :weight,
satscore = :satscore,
gpa = :gpa';
$s = $pdo->prepare($sql);
$s->bindValue(':name', $_POST['name']);
$s->bindValue(':age', $_POST['age']);
$s->bindValue(':position', $_POST['position']);
$s->bindValue(':height', $_POST['height']);
$s->bindValue(':weight', $_POST['weight']);
$s->bindValue(':satscore', $_POST['satscore']);
$s->bindValue(':gpa', $_POST['gpa']);
$s->execute();
$one = $pdo->lastInsertId();
}
catch (PDOException $e)
{
$error = 'Error adding submitted player profile.' . $e->getMessage();
include 'error.html.php';
exit();
}
//PREVIOUS CLUBS TABLE INSERT
try
{
$sql = 'INSERT INTO previousclubs SET
name = :previousclubs';
$s = $pdo->prepare($sql);
$s->bindValue(':previousclubs', $_POST['previousclubs']);
$s->execute();
$two = $pdo->lastInsertId();
}
catch (PDOException $e)
{
$error = 'Error adding previous club.' . $e->getMessage();
include 'error.html.php';
exit();
}
//PLAYER PREVIOUS CLUB INSERT
try
{
$sql = "INSERT INTO playerpreviousclubs SET
playerid = '$one',
previousclubid = '$two'";
$s = $pdo->prepare($sql);
$s->bindValue(':playerid', $_POST['playerid']);
$s->bindValue(':previousclubid', $_POST['previousclubid']);
$s->execute();
}
catch (PDOException $e)
{
$error = 'Error adding player previous club look up data.' . $e->getMessage();
include 'error.html.php';
exit();
}
//LINKS TABLE INSERT
try
{
$sql = "INSERT INTO links SET
link = :link,
playerid = '$one'";
$s = $pdo->prepare($sql);
$s->bindValue(':link', $_POST['link']);
$s->bindValue(':playerid', $_POST['playerid']);
$s->execute();
}
catch (PDOException $e)
{
$error = 'Error adding link for player.' . $e->getMessage();
include 'error.html.php';
exit();
}
header('Location: .');
exit();
}
这给了我以下错误:
注意:未定义索引:第 84 行 C:\Program Files (x86)\Apache Software Foundation\Apache2.2\htdocs\connect\players\index.php 中的 playerid
注意:未定义索引:第 85 行 C:\Program Files (x86)\Apache Software Foundation\Apache2.2\htdocs\connect\players\index.php 中的 previousclubid
注意:未定义索引:第 103 行 C:\Program Files (x86)\Apache Software Foundation\Apache2.2\htdocs\connect\players\index.php 中的 playerid
为 player.SQLSTATE [HY093] 添加链接时出错:参数号无效:绑定变量的数量与令牌的数量不匹配
如果我删除“//LINKS TABLE INSERT”下的所有代码,那么它可以工作,所以我认为问题就在这里,但我还需要这个表来存储 $one 值。
有任何想法吗?