ios5 - iOS的推特框架支持自动分享吗？

Question

我有一个名为 twitter 的按钮，当我通常单击此按钮时，会显示一个用于发推文的视图，即TWTweetComposeViewController。我有两种发推文的方式，即自动分享和正常分享。正常分享工作得很好，但我怀疑如何在自动分享中做同样的事情，这意味着当我点击推特按钮而不是显示时自动发一些默认消息视图并TWTweetComposeViewController单击完成按钮。

Answer 1

最后，我在 ios5 中搜索了很多与 Twitter 相关的问题，还阅读了 twitter 开发者文档并尝试了这个答案。我认为这是进行自动共享的解决方案之一。

ACAccountStore *account = [[ACAccountStore alloc] init];
        ACAccountType *accountType = [account accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];

        // Request access from the user to access their Twitter account
        [account requestAccessToAccountsWithType:accountType withCompletionHandler:^(BOOL granted, NSError *error) {
            // Did user allow us access?
            if (granted == YES)
            {
                // Populate array with all available Twitter accounts
                NSArray *arrayOfAccounts = [account accountsWithAccountType:accountType];

                // Sanity check
                if ([arrayOfAccounts count] > 0) 
                {
                    // Keep it simple, use the first account available
                    ACAccount *acct = [arrayOfAccounts objectAtIndex:0];

                    NSURL *url = 
                    [NSURL URLWithString:
                     @"https://upload.twitter.com/1/statuses/update_with_media.json"];

                    //  Create a POST request for the target endpoint
                    TWRequest *request = 
                    [[TWRequest alloc] initWithURL:url 
                                        parameters:nil 
                                     requestMethod:TWRequestMethodPOST];

                    //  self.accounts is an array of all available accounts; 
                    //  we use the first one for simplicity
                    [request setAccount:acct];

                    //  The "larry.png" is an image that we have locally
                    UIImage *image = (UIImage *)[dictionarydata valueForKey:@"image"];
                    NSLog(@"%@",image);
                    if (image!=nil) {

                        //  Obtain NSData from the UIImage 
                        NSData *imageData = UIImagePNGRepresentation(image);


                        //  Add the data of the image with the 
                        //  correct parameter name, "media[]"
                        [request addMultiPartData:imageData 
                                         withName:@"media[]" 
                                             type:@"multipart/form-data"];

                        // NB: Our status must be passed as part of the multipart form data
                        NSString *status = [NSString stringWithFormat:@"%@ %@ %@",[dictionaryData valueForKey:@"firstname"],[dictionaryData valueForKey:@"lastname"],[dictionarydata valueForKey:@"title"]];

                        //  Add the data of the status as parameter "status"
                        [request addMultiPartData:[status dataUsingEncoding:NSUTF8StringEncoding] 
                                         withName:@"status" 
                                             type:@"multipart/form-data"];
                        //  Perform the request.  
                        //    Note that -[performRequestWithHandler] may be called on any thread,
                        //    so you should explicitly dispatch any UI operations to the main thread 
                        [request performRequestWithHandler:
                         ^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
                             NSDictionary *dict = 
                             (NSDictionary *)[NSJSONSerialization 
                                              JSONObjectWithData:responseData options:0 error:nil];

                             // Log the result
                             NSLog(@"%@", dict);

                             dispatch_async(dispatch_get_main_queue(), ^{
                                 // perform an action that updates the UI...
                             });
                         }];
                    }else{
                        NSURL *url = [NSURL URLWithString:@"https://api.twitter.com/1/statuses/update.json"];
                        NSDictionary *p = [NSDictionary dictionaryWithObjectsAndKeys:
                                           [NSString stringWithFormat:@"%@ %@ %@",[dictionaryData valueForKey:@"firstname"],[dictionaryData valueForKey:@"lastname"],[dictionarydata valueForKey:@"title"]], @"status",
                                           nil
                                           ];
                        TWRequest *postRequest = [[TWRequest alloc]
                                                  initWithURL:   url
                                                  parameters:    p
                                                  requestMethod: TWRequestMethodPOST
                                                  ];

                        // Post the request
                        [postRequest setAccount:acct];

                        // Block handler to manage the response
                        [postRequest performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
                            NSLog(@"Twitter response, HTTP response: %i", [urlResponse statusCode]);
                        }];
}
                }
            }
        }];

Answer 2

如果您一直在使用 Twitter 框架，您可以这样做：

NSString *statusesShowEndpoint = @"https://api.twitter.com/1.1/statuses/update.json";
NSDictionary *params = @{@"status": @"Great101 - https://share.livefrom.me/p/md5mrCp"};

NSError *clientError;
NSURLRequest *request = [[[Twitter sharedInstance] APIClient]
                         URLRequestWithMethod:@"POST"
                         URL:statusesShowEndpoint
                         parameters:params
                         error:&clientError];

if (request) {
    [[[Twitter sharedInstance] APIClient]
     sendTwitterRequest:request
     completion:^(NSURLResponse *response,
                  NSData  *data,
                  NSError *connectionError) {
         if (data) {
             // handle the response data e.g.
             NSError *jsonError;
             NSDictionary *dicResponse = [NSJSONSerialization
                                           JSONObjectWithData:data
                                           options:0
                                           error:&jsonError];
             NSLog(@"%@",[dicResponse description]);
         }
         else {
             NSLog(@"Error code: %ld | Error description: %@", (long)[connectionError code], [connectionError localizedDescription]);
         }
     }];
}
else {
    NSLog(@"Error: %@", clientError);
}